help brain freeze on mid / len / right

I have say:

C:\blah\foo\bar.txt

I need just bar.txt...

I see InStr returns first occurence..I probably need last occurence?

Jon

Use InStrRev() to get last occurence of backslash and then Mid(... pos +1):

VB Code:

Private Sub Command1_Click()
Dim sText$
 
    sText = "C:\blah\foo\bar.txt"
    MsgBox Mid(sText, InStrRev(sText, "\") + 1)
 
End Sub

or...

VB Code:

Dim sText$
Dim strParts() As String
 
    sText = "C:\blah\foo\bar.txt"
    
    strParts = Split(sText, "\")
    MsgBox strParts(UBound(strParts))