anyone has an idea on how to produce 9 random letters?

i am working on a password encryptor/decryptor and i need to produce 9 random characters from a-z every click of a button. anyone who has and idea or suggestion please help. thanks to all!!!!

VB Code:

MsgBox Chr(Int((122 - 97 + 1) * Rnd) + 97)

Mendhak, are you really in Ulaan Batoor?

Ugu'i.
:)

Wow, I am impressed. Last time I was there was in 1997, didn't think too much of it. (Off topic, I know, sorry) What nationality are you/what do you there?

Quote:

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Originally posted by madjon
Wow, I am impressed. Last time I was there was in 1997, didn't think too much of it. (Off topic, I know, sorry) What nationality are you/what do you there?

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I'm currently defacing the Great Wall of China with my Great Can of Spray Pain. :afrog:

(Off-topic stuff in PMs... or this one will get deleted.)

thanks Mendhak.. very big help. Thank you!

the code u gave me when first fired always give me <snphhuatv> and unloaded. then when ran again gives me the same value <snphhuatv>

what i need is when the function is called it genereates an entirely new set of 9 characters.

need answers ASAP. Thanks!

Post the code you're using.

Did you remember to use the Randomize statement?

VB Code:

Public Function generatePassword() As String
Dim x As Integer
Dim tmpStr As String
 
For x = 1 To 9
    tmpStr = tmpStr & Chr(Int((122 - 97 + 1) * Rnd) + 97)
Next
generatePassword = tmpStr
End Function

this is the code try putting this function on a form and have a button call it. notice that the first set will always give you = snphhuatv =

VB Code:

public Function generatePassword() As String
Dim x As Integer
Dim tmpStr As String
Randomize
For x = 1 To 9
    tmpStr = tmpStr & Chr(Int((122 - 97 + 1) * Rnd) + 97)
Next
generatePassword = tmpStr
End Function

With the randomize function there, this will not happen

You need randomize only once, put it in form_load or sub main()