The answer is 16 but I can only get 8 when I solve it
http://vbforums.com/attachment.php?s=&postid=1699030
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The answer is 16 but I can only get 8 when I solve it
http://vbforums.com/attachment.php?s=&postid=1699030
10^(x*y) = (10^x)^y
so:
10^(log10(2) * 4) = (10^log10(2))^4
x^logx(y) = y
so:
(10^log10(2))^4 = 2^4 = 16
thanks, I kept running in the loop of multiplying the 4*2=8
A similar approach based on the fact that
log(xy) = y * log(x)
4 log10(2) = log10(24) = log10(16)
and by definition, 10log(something) = something