How do I display the results of an xslt tranformation? RESOLVED

I'm hitting a web service and request records. These records are returned as an xml string. When I get this string I have to apply an xsl style sheet to the data and present it as an html table.

If I create an xml file from the retruned string and apply the xsl stylesheet I created, it give nice results. I just can't figure out how to take the string returned and directly apply the style sheet to it and display the results in an asp page.

Can someone point me in the right direction?

XML allows inline style sheets and links

Try appending the stylesheet at the top after the <XML> tag...
try that first.

If that fails or won't work for your project, here's a snippet I lifted out of our project that uses a XSLSortTransform on the elements..

VB Code:

'the next three lines simply load XML from a database,( you can use a file or memorystream, whatever)..
 'and assigns appends it a stringbuilder
 While dreader.Read
            xmlstring.Append(dreader(0))
        End While
[b] 'heres the meat[/b]
        Dim xmldoc As New System.Xml.XmlDocument
 
        'here we assign the actual XML to an empty XMLdocument 
       xmldoc.LoadXml(xmlstring.ToString)
 
 
       'Define a transform...
        Dim myXslTransform As New XslTransform
        'load the XSLT
        myXslTransform.Load(Page.MapPath("DropDownTree.xslt"))
        'create a readable stream from the transform
        Dim xr As XmlReader = myXslTransform.Transform(xmldoc, Nothing)
 
 
        'create a new empty doc        
        Dim Sorteddoc As New System.Xml.XmlDocument
 
        'assign the transformed XML to the new empty doc
        Sorteddoc.Load(xr)

In reality, depending on the length of the XSLT... you could simply build a XSLT using a stringbuilder and create an XSLTransform from that... all inside your code.

Thanks!

I ended up using an XML Control on the web form. I just set the DocumentContent property to the xml string and the TransformSource property to the xsl file. It seems to work pretty well.