PopUpMenu; x y coordinates [WORKAROUND FOUND]

Hi everyone,

I'm facing a strange problem with the PopUpMenu method. I'm building a plugin for Internet Explorer, and therefore my project is an ActiveX DLL. So when executed the Internet Explorer window hosts my DLL.

Now I simply want to pop up a menu from a button on my IE Toolbar. Usually I use the following code for that:

VB Code:

PopupMenu "mnuFile", , Command1.Left, Command1.Top + Command1.Height

In this case, however, it does not work at all. The menu appears somewhere on the page instead of directly under the button.

See the screenshot for an example of what I mean (the menu appears after clicking the 'Content Creator' button, and should be directly under the button).

Now there must be a way to get that menu to pop up where I want it to. Any thoughts? :)

Wont

VB Code:

PopupMenu mnuFile

work?

The other things are optional...

MSDN:
PopupMenu Method Example
This example displays a pop-up menu at the cursor location when the user clicks the right mouse button over a form. To try this example, create a form that includes a Menu control named mnuFile (mnuFile must have at least one submenu). Copy the code into the Declarations section of the form, and press F5.

VB Code:

Private Sub Form_MouseDown (Button As Integer, Shift As Integer, X As Single, Y As Single)
   If Button = 2 Then
      PopupMenu mnuFile
   End If
End Sub

See?
:confused:

PopupMenu pops up at the current mouse coordinates. In that case the location of the menu would depend on where the button is clicked. That doesn't look very well. :(

Anyway, I've found a workaround. I wanted the menu to expand when the user clicked a button; but since I made that button myself I simply included it in the ActiveX control. :)

It still remains odd, though. :sick: