initializing a 2D array?

Apparently when you declare a 2D array you can't initialize the size of the second dimension. This what I'm doing right now...

PHP Code:

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            byte[][] intensityVals = new byte[height][];
for (int i=0; i<height; i++)
      intensityVals[i] = new byte[width]; 


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isn't there a better or shorter way?

VB Code:

[b]Single-dimensional array[/b]
int[] numbers = new int[5];
 
[b]Multidimensional array[/b]
string[,] names = new string[5,4];
 
[b]Array-of-arrays (jagged array)[/b]
byte[][] scores = new byte[5][];

Quote:

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Originally posted by Memnoch1207

VB Code:

[b]Single-dimensional array
int[] numbers = new int[5];
 
[b]Multidimensional array[/b]
string[,] names = new string[5,4];
 
[b]Array-of-arrays (jagged array)[/b]
byte[][] scores = new byte[5][];

[/B]

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hmm interesting:D thank you! second one was what I was looking for...

umm I still dont understand the difference between declaring it like [x][y] versus [x,y].... both seem to work the same? hmm (is it just that they work the same but are different structurally?)

excuse my idiot-ness btw :wave: