last 14 dates [Resolved]

I'm trying to put the last 14 dates of the calender in a dropdown box. I thought you could just subtract a number from the date value, but I guess not. Can someone tell me how to get the last 14 dates into an array? The following doesn't work.

PHP Code:

---

$myarr = array(0 => (date("n/j/Y")-14), (date("n/j/Y")-13), (date("n/j/Y")-12), (date("n/j/Y")-11), (date("n/j/Y")-10), (date("n/j/Y")-9), (date("n/j/Y")-8), (date("n/j/Y")-7), (date("n/j/Y")-6), (date("n/j/Y")-5), (date("n/j/Y")-4), (date("n/j/Y")-3), (date("n/j/Y")-2), (date("n/j/Y")-1), date("n/j/Y"));
    $i=0;
    for($i=0;$i<15;$i++)
        echo $myarr[$i] . "<br>"; 


---

I use this function to produce a drop down list of days. You may need to modify it to suit your needs though. If you use a UNIX timestamp then you can add and subtract from dates as easy as you do from numbers:

PHP Code:

---

function maketimes($maxdays, $endofday = 0)
{
    $seconds_day = 60 * 60 * 24;
    $time = time(); // returns a UNIX timestamp

    for ($x = 0; $x < $maxdays; $x++)
    {
        $array_date = getdate($time - ($x * $seconds_day));
        $start_of_day = mktime (0, 0, 0, $array_date['mon'], $array_date['mday'], $array_date['year']);
            
        if ($endofday) $start_of_day += $seconds_day - 1;

        echo('<option value="' .      $start_of_day . '">' . 
date("l j F Y", $start_of_day) . "</option>\n");
    }

} 


---

Ok... that works good... but how do I put those values into an array instead of the select box? (I will have to have an unknown number of dropdown boxes containing the dates.)

I hate arrays + php. :(

if $start_of_day holds the date, in the for loop, then something like this maybe:

PHP Code:

---

myArr = array() //put this before the loop
myArr[count(myArr)] = $start_of_day //instead of making the drop down menu. 


---

Here's a bit shorter way to display the last 14 days (including today):

PHP Code:

---

<?php

    for ($i = 13; $i >= 0; $i--) {
        // Save in array:
        $arrDates[] = date('m-d-Y', strtotime($i . ' days ago'));
        echo $arrDates[count($arrDates) - 1] . '<br />';
    }

?>

---

excellent. Now... Hobo, if you could, please transfer all your knowledge to a cd or a dvd (you may need a few) and then ship that over to me, k? Thanks. :D ;)

Quote:

---

Originally posted by ober5861
excellent. Now... Hobo, if you could, please transfer all your knowledge to a cd or a dvd (you may need a few) and then ship that over to me, k? Thanks. :D ;)

---

Sure, for the remarkable low price of $399.99, I can make that happen. And I can make it all fit on a 1.5MB floppy, as well.

What a deal, huh? ;)

Do you accept Visa? :D