Active Directory...How to get users in a group?

I need to get all the login names and corrisponding friendly names from active directory that are in a certain group. How would I do this?

Bumping this because it is pretty important for me to continue my project...

Searching MSDN came up with this , haven't tried it, though.

Yea, I have tried all the examples I could find. I can get a complete listing of AD users, but I can't get them from a single group right now.

Here you go, I had to convert it from some code I previously did that got all groups a user was in. I see what you mean about not finding much info on how to reverse that and get all users in a group but this should work:

VB Code:

'syntax
ListBox1.Items.AddRange(GetMembersOfGroup("edneeis.local", "Administrators"))
 
    Private Function GetMembersOfGroup(ByVal domain As String, ByVal group As String) As String()
        'set domain path
        Dim de As New DirectoryEntry(String.Format("LDAP://{0}", domain))
        Dim srch As New DirectorySearcher(de)
        'filter find all groups with the name provided
        srch.Filter = String.Format("(&(objectClass=group)(Name={0}))", group)
        Dim al As New ArrayList
        For Each res As SearchResult In srch.FindAll
            'get all members
            For Each obj As Object In res.Properties("Member")
                'trim to a more legible name
                al.Add(TrimToName(obj))
            Next
        Next
        Return CType(al.ToArray(GetType(String)), String())
    End Function
 
    Private Function TrimToName(ByVal path As String) As String
        Dim parts() As String = path.Split(",")
        Return parts(0).Replace("CN=", String.Empty)
    End Function

Thanks, I am not on a network until next week now, so I will have to give it a try then.

Appreciate it.

Hey, that code is not working. You should come back and make it work :)

Quote:

---

Originally Posted by dani2

Hey, that code is not working. You should come back and make it work :)

---

You may want to be more specific then that. It works when I run it. What makes you say otherwise?