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Hi,
I wonder if anyone can help with the following.
I have to calculate the graduations on a dipstick used to measure the amount of liquid remaining in a tank with an oval section. This appears to be a problem of Integration (maths meaning).
What I have to do is to calculate the area of that part of an ellipse between a line parrellel to the horizontal axis and the circumference.
I don't suppose there are any predefined VB.NET functions. Any ideas??
Help!! (Please)
I have been given the Integration formula but I do not know how to implement Integration! Any one know if I could find enlightenment on the Internet?
Hi
Is it requirement that you must use vb to solve this problem?
If not i would advise you to use a high level language maths package such as mathematica or maple.
Using VB means not just solving the problem but implementing any mechanisms to do so, this is possible but sounds a little like a University Dissertation project or something (i.e too much work)
not the answer you were hoping for i suspect...
What's the formula?
HI,
"Is it requirement that you must use vb to solve this problem?"
No, but once I understand what the formula requires, re-iteration should be a breeze in VB.
"What's the formula?"
I have difficulty in posting the formula, which is not a formula as we are used to in programming. It is a re-iteration of an infinite calculation until a negligible result is achieved.
The following shows how the formula is derived (if it means anything to anyone!!)
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let's say your ellipse has it's centre on the origin, and goes through the points
x=0,y=b; x=0,y=-b; x=a,y=0; x=-a,y=0
i.e. it has width 2a and height 2b. now the equation of the ellipse is given by
(x/a)^2 + (y/b)^2 = 1
i can prove this from something else if you want, but usually it is taken as the defenition of an ellipse.
now you want to find the area between the line y=k and the ellipse, k<b. to do this rearrange the equation:
x=a@(1 - (y/b)^2 ) ("@" should be a square root sign which I do not have on my keyboard)
and concentrate on y and x both greater than 0. now the area between the "top" of the ellipse and the line y=k is given by
y=b y=k a@(1 - (y/b)^2 ) dy. ("y=b" & "y=k" are interlined and preceded by a squiggle which looks like a vertically extended "S")
you should be able to do this integral with a simple substitution - let y = bsinq ("q" is the greek letter Theta which stands for an angle)
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Any help would be greatly appreciated!!!
:confused: :confused: :confused:
i'm afraid that's a bit beyond me. it's been a few years since I did A-level maths!
Try the maths forum:
http://www.vbforums.com/forumdisplay.php?s=&forumid=20
Hi,
I could handle A level maths, but this is way beyond that. It is more like a Degree Thesis!!
I did not realise there was a Maths Forum here:eek: :eek:
I have taken up your suggestion, Many thanks.