Can someone check this code to see If I could make it smaller

I was told to make a program that makes the user input a numerical value of 1-999 and the computer prints out that number in letters (i.e "123" = "One hundred and twenty three"). This is the solution I came up with:

VB Code:

Dim valu As Integer
Option Explicit
 
 
Private Sub Command1_Click()
lblConverted.Caption = ""
valu = val(Text1.Text)
 
If valu >= 900 Then
    valu = valu - 900
    lblConverted.Caption = "Nine Hundred "
ElseIf valu >= 800 Then
    valu = valu - 800
    lblConverted.Caption = "Eight Hundred "
ElseIf valu >= 700 Then
    valu = valu - 700
    lblConverted.Caption = "Seven Hundred "
ElseIf valu >= 600 Then
    valu = valu - 600
    lblConverted.Caption = "Six Hundred "
ElseIf valu >= 500 Then
    valu = valu - 500
    lblConverted.Caption = "Five Hundred "
ElseIf valu >= 400 Then
    valu = valu - 400
    lblConverted.Caption = "Four Hundred "
ElseIf valu >= 300 Then
    valu = valu - 300
    lblConverted.Caption = "Three Hundred "
ElseIf valu >= 200 Then
    valu = valu - 200
    lblConverted.Caption = "Two Hundred "
ElseIf valu >= 100 Then
    valu = valu - 100
    lblConverted.Caption = "One Hundred "
End If
 
If valu >= 90 Then
    valu = valu - 90
    lblConverted.Caption = lblConverted.Caption & "and Ninty-"
ElseIf valu >= 80 Then
    valu = valu - 80
    lblConverted.Caption = lblConverted.Caption & "and Eighty-"
ElseIf valu >= 70 Then
    valu = valu - 70
    lblConverted.Caption = lblConverted.Caption & "and Seventy-"
ElseIf valu >= 60 Then
    valu = valu - 60
    lblConverted.Caption = lblConverted.Caption & "and Sixty-"
ElseIf valu >= 50 Then
    valu = valu - 50
    lblConverted.Caption = lblConverted.Caption & "and Fifty-"
ElseIf valu >= 40 Then
    valu = valu - 40
    lblConverted.Caption = lblConverted.Caption & "and Fourty-"
ElseIf valu >= 30 Then
    valu = valu - 30
    lblConverted.Caption = lblConverted.Caption & "and Thirty-"
ElseIf valu >= 20 Then
    valu = valu - 20
    lblConverted.Caption = lblConverted.Caption & "and Twenty-"
End If
 
If valu >= 19 Then
    lblConverted.Caption = lblConverted.Caption & "and Ninteen"
 
ElseIf valu >= 18 Then
    lblConverted.Caption = lblConverted.Caption & "and Eighteen"
 
ElseIf valu >= 17 Then
    lblConverted.Caption = lblConverted.Caption & "and Seventeen"
 
ElseIf valu >= 16 Then
    lblConverted.Caption = lblConverted.Caption & "and Sixteen"
 
ElseIf valu >= 15 Then
    lblConverted.Caption = lblConverted.Caption & "and Fifteen"
 
ElseIf valu >= 14 Then
    lblConverted.Caption = lblConverted.Caption & "and Fourteen"
 
ElseIf valu >= 13 Then
    lblConverted.Caption = lblConverted.Caption & "and Thirteen"
 
ElseIf valu >= 12 Then
    lblConverted.Caption = lblConverted.Caption & "and Twelve"
 
ElseIf valu >= 11 Then
    lblConverted.Caption = lblConverted.Caption & "and Eleven"
 
ElseIf valu >= 10 Then
    lblConverted.Caption = lblConverted.Caption & "Ten"
 
ElseIf valu >= 9 Then
    lblConverted.Caption = lblConverted.Caption & "Nine"
 
ElseIf valu >= 8 Then
    lblConverted.Caption = lblConverted.Caption & "Eight"
 
ElseIf valu >= 7 Then
    lblConverted.Caption = lblConverted.Caption & "Seven"
 
ElseIf valu >= 6 Then
    lblConverted.Caption = lblConverted.Caption & "Six"
 
ElseIf valu >= 5 Then
    lblConverted.Caption = lblConverted.Caption & "Five"
 
ElseIf valu >= 4 Then
    lblConverted.Caption = lblConverted.Caption & "Four"
 
ElseIf valu >= 3 Then
    lblConverted.Caption = lblConverted.Caption & "Three"
 
ElseIf valu >= 2 Then
    lblConverted.Caption = lblConverted.Caption & "Two"
 
ElseIf valu >= 1 Then
    lblConverted.Caption = lblConverted.Caption & "One"
    
End If
 
 
 
End Sub

SandmanSamR

Yeah Man, Put those things in an array and only reference them once.I will just give you the concept.

VB Code:

Arr1 = Array("","One","Two","Three",...,"Ninteen")
Arr10 = Array("","Ten","Twenty","Thirty",...,"Ninety")
 
x100 = Int(value / 100)
x10 =  Int((value - (x100 * 100)))
x1 =  (value - (x100 * 100) - (x10 * 10))
 
Arr1(x100) "Hundred and " & Arr10 (x10) & " Dollars"

You get the idea?

I just started vb this year. We have yet to get to arrays. Looking at that code though I say I have some understanding of whats going on. Would you mind summerizing so I can assure myself of what exaclty is going on so that I can use this if and when I need it in the future

SandmanSamR

OK, backing up...An array is just a place to hold a series of like data types where you can reference them by an index.

From the code I gave you:

Arr1(1) = "One"
Arr1(2) = "Two" ....

Arr10(1) = "Ten"
Ar10(2) = "Twenty" ...

So we can reference any item in the array by giving it's index to it. Now when taking the statement:

x100 = Int(value / 100)

with value equal to 525

x100 = Int(525 / 100) which equals 5

Now going to the array we get:

Arr1(5) = "Five"

And we do that for each value and array. Getting clearer?

Wrong forum

Randem has the right idea, but you have to do a little more checking than that. Or else you would be printing "hundred and" even though you just entered 20 in the text box. Here is some code that works.

VB Code:

Private Sub Command1_Click()
    Dim sNum(1 To 9) As String
    Dim sOnes(1 To 9) As String
    
    Dim Hundred As Integer
    Dim Ten As Integer
    Dim One As Integer
    
    sNum(1) = "Eleven"
    sNum(2) = "Twelve"
    sNum(3) = "Thir"
    sNum(4) = "Four"
    sNum(5) = "Fif"
    sNum(6) = "Six"
    sNum(7) = "Seven"
    sNum(8) = "Eigh"
    sNum(9) = "Nine"
    
    sOnes(1) = "One"
    sOnes(2) = "Two"
    sOnes(3) = "Three"
    sOnes(4) = "Four"
    sOnes(5) = "Five"
    sOnes(6) = "Six"
    sOnes(7) = "Seven"
    sOnes(8) = "Eight"
    sOnes(9) = "Nine"
    
    
    lblConverted.Caption = ""
    
    If Len(Text1) = 3 Then
        Hundred = CInt(Left$(Text1, 1))
        Ten = CInt(Mid$(Text1, 2, 1))
        One = CInt(Right$(Text1, 1))
    ElseIf Len(Text1) = 2 Then
        Hundred = 0
        Ten = CInt(Left$(Text1, 1))
        One = CInt(Right$(Text1, 1))
    ElseIf Len(Text1) = 1 Then
        Hundred = 0
        Ten = 0
        One = Text1
    Else
        Hundred = 0
        Ten = 0
        One = 0
    End If
    
    If Hundred > 0 Then
        lblConverted = sOnes(Hundred) & " Hundred "
        If Ten > 0 Or One > 0 Then
            lblConverted = lblConverted & " and "
        End If
    End If
    
    If Ten > 0 Then
        If Ten = 1 Then
            Select Case One
                Case 1, 2
                    lblConverted = lblConverted & sNum(One)
                Case Else
                    lblConverted = lblConverted & sNum(One) & "teen"
            End Select
        Else
            Select Case Ten
                Case 2
                    lblConverted = lblConverted & "Twenty"
                Case Else
                    lblConverted = lblConverted & sNum(Ten) & "ty"
            End Select
            
            If One > 0 Then
                lblConverted = lblConverted & "-"
            End If
        End If
    End If
   
   'This was the missing code. I don't know how that didnlt copy 
    If Ten <> 1 Then
        If One > 0 Then
            lblConverted = lblConverted & sOnes(One)
        End If
    End If
End Sub

[edit]
Oops somehow I lost some of the code. Hold on.

cool i get it. Quick question though, instead of

VB Code:

x100 = Int(525 / 100) which equals 5

could you have done

VB Code:

x100 = (525 \ 100) which equals 5

?

Maldrid

That is what a concept is correct? I did not plan to do what seems like his homework for him.

Wrong forum

How you figure?

SandmanSamR

Well sort of. It depends on how the x100 was defined. I like to take that out of the equation and alway return an integer. That way it always works no matter what numeric data type was defined.

525 / 100 = 5.25

or as an integer

525 / 100 = 5

Quote:

---

Originally posted by SandmanSamR
Wrong forum

How you figure?

---

Uh.... look at your title, then look at the forums... you can figure it out.

I did not plan to do what seems like his homework for him.

The original program I wrote was complete. I didnt need someone to finish it for me. I wanted to know if I could cut down on the repetitivness of it. Thanks for originally not showing me hard code and concept instead though, I would rather that then just shown what to copy and paste.

SandmanSamR

No offense, but lots of people attempt to get their homework done by unsuspecting members here. I saw what you were doing and using all those IF's is something a beginner would do.

So, I thought it might be a homework assignment.

525 / 100 = 5.25

or as an integer

525 / 100 = 5


thats why I wrote 525\100 not 525/100. I wrote \ instead of /

Randem-

You are absolutely right. Sorry if it sounded like I was trying to say you were wrong. I knew you were just giving him the concept not the exact answer.



My previous code did not consider Ten. Here is the revised code.

VB Code:

Private Sub Command1_Click()
    Dim sNum(1 To 9) As String
    Dim sOnes(1 To 9) As String
    
    Dim Hundred As Integer
    Dim Ten As Integer
    Dim One As Integer
    
    sNum(1) = "Eleven"
    sNum(2) = "Twelve"
    sNum(3) = "Thir"
    sNum(4) = "Four"
    sNum(5) = "Fif"
    sNum(6) = "Six"
    sNum(7) = "Seven"
    sNum(8) = "Eigh"
    sNum(9) = "Nine"
    
    sOnes(1) = "One"
    sOnes(2) = "Two"
    sOnes(3) = "Three"
    sOnes(4) = "Four"
    sOnes(5) = "Five"
    sOnes(6) = "Six"
    sOnes(7) = "Seven"
    sOnes(8) = "Eight"
    sOnes(9) = "Nine"
    
    
    lblConverted.Caption = ""
    
    If Len(Text1) = 3 Then
        Hundred = CInt(Left$(Text1, 1))
        Ten = CInt(Mid$(Text1, 2, 1))
        One = CInt(Right$(Text1, 1))
    ElseIf Len(Text1) = 2 Then
        Hundred = 0
        Ten = CInt(Left$(Text1, 1))
        One = CInt(Right$(Text1, 1))
    ElseIf Len(Text1) = 1 Then
        Hundred = 0
        Ten = 0
        One = Text1
    Else
        Hundred = 0
        Ten = 0
        One = 0
    End If
    
    If Hundred > 0 Then
        lblConverted = sOnes(Hundred) & " Hundred "
        If Ten > 0 Or One > 0 Then
            lblConverted = lblConverted & " and "
        End If
    End If
    
    If Ten > 0 Then
        If Ten = 1 Then
            If One = 0 Then
                lblConverted = lblConverted & "Ten"
            Else
                Select Case One
                    Case 1, 2
                        lblConverted = lblConverted & sNum(One)
                    Case Else
                        lblConverted = lblConverted & sNum(One) & "teen"
                End Select
            End If
        Else
            Select Case Ten
                Case 2
                    lblConverted = lblConverted & "Twenty"
                Case Else
                    lblConverted = lblConverted & sNum(Ten) & "ty"
            End Select
            
            If One > 0 Then
                lblConverted = lblConverted & "-"
            End If
        End If
    End If
    
    If Ten <> 1 Then
        If One > 0 Then
            lblConverted = lblConverted & sOnes(One)
        End If
    End If
End Sub

SandmanSamR

Wasn't even aware that you could do that. But it would just seem to me that the notation used could confuse someone who overlooked or did not know that was possible.

lol, Maldrids code is almost as long as mine. I would sacrifice having 20 = "and twenty" for a smaller code, should I just go with randems? (Plus I'm getting confused reading maldrids code lol)

Yea you can go with randems suggestion since you are more comfortable with it. :)

SandmanSamR

Let me see your code when you are done. What you want to accomplish should take the most twenty lines.

Quote:

---

Originally posted by SandmanSamR
Wrong forum

How you figure?

---

It is probably better here where I have just moved it.

if i were you i'd code it like this:
[sorry my code is not neat as i wrote here,
not on vb]

VB Code:

num=563
 
dim x(9) as string
dim y(9) as string
dim z(9) as string
 
x(0) = ""
x(1) = "one"
x(2) = "two"
'....
'....
x(9) = "nine"
 
y(0) = ""
y(1) = ""
y(2) = "twen"
y(3) = "thir"
'....
'....
y(9) = "nine"
 
'dont need them :D
'dim i as long
'for i = 1 to 9
'zz(i) = xx(i) & " hundred"
'next i
 
'now a 563 should be segmented to 5 / 6 / 3
dim xx as byte, yy as byte, zz as byte
xx = num mod 10
yy = (num \ 10) mod 10
zz = num \ 100
 
dim str as string
 
str = y(yy) & "ty " & x(xx)
 
'special case treatment for yy=1, eg. 11, 12, 215
if yy=1 then
select case xx
case 0: str="ten"
case 1: str="eleven"
case 2: str="twelve"
case else: str = y(xx) & "teen"      'lines saved here ;)
end select
end if
 
if str = "ty " then    'special cases like: 100 , 200 , 300 ...etc
str = x(zz) & " hundred"
else
str= x(zz) & " hundred and " & str
end if

ZaidGS


Trade 10 lines of code for all of that???? Why????

Quote:

---

Originally posted by randem
ZaidGS


Trade 10 lines of code for all of that???? Why????

---

so u got a 10 line code ?! ha ?!

my code is cleanest so far (i guess)

ZaidGS


You wish, You should really actually read the posts.

sorry your posts are too
brief so that they become un-understandable,
will you please tell me whats wrong ??!

ZaidGS

Wrong???, Nothing is wrong. It's just way too much code for a simple task (expecially when you claim it's the shortest). The post is looking for short code, not just code that works. You code will turn out longer than the original posted code.

The reason my post are short is they get to the point quicker.

ok, i'll take off some lines ;)

if you dont believe me count lines :P
u'll know mine is shorter, even without the
lines i removed!!

ZaidGS

Take a look here: Convert Dollar Amount into Words

A simple project that does it all.

wow, y its not posted here, i dont see it :confused: :blush:

ZaidGS

Click on the link.

i already clicked on the link, i just meant that
its not been posted so i didnt know of its
existance.
sorry, if that was because of ignorance from me !!!:confused:

ZaidGS

Oh, Sorry, I thought you meant you could not download it. I don't want to post everything I did here, unless asked for I guess. I could put it in the codebank, but this was the first request for something like this from the forum.