how do u find the angle of these points?

Hello everyone, I was reading next semesters programming book and I can't even figure out how to do this problem on paper, so It doesn't look like i'll be programming it anytime soon. Here's my question, They say, design and implement a class called circle_location to keep track of the postion of a single point that travels around a circle. An object of this clas records the position of the point as an angle, measured in a clockwise direction from the top of the circle. Programming this isn't my problem, but I'm confused on how i'm suppose to figure out the angle of the point. So say I have a point at (0,0) and (3,3) this would make a line then I could draw a vertical line down to make a right angle, but how would I find the angle of that? with just given 2 points? Or am i misunderstanding what they really want me to do?
Thanks! :wave:

google on trigonometry

You can use tan^-1 (abs(y₁ - y₂))/(abs(x₁ - x₂))

With the originating point being (x₂, y₂) and the other being (x₁, y₁). Now, you'll have to use whether (y₁ - y₂) and (x₁ - x₂) or positive or negative to tell you which quadrant it's in.

- , + = quadrant 4
- , - = quadrant 3
+ , - = quadrant 2
+ , + = quadrant 1

I'm sure there are other ways (like somehow using the parametric representation of a circle and solving for T), but that *should* work with some fiddling around.

Thanks jemidiah, That will work great!
:D

One thing I remembered: when x₁ - x₂ = 0, you'd get a divide by zero error (duh), so the angle'll be 90 :)

yeh its infinity and tan 90 is infinity

I haven't nit-picked for a while, so here goes:

tan90^o is infinite not infinity, they are different.

I thought tan 90° was not defined, likewise cot 0° csc 0° and sec 90°

They're all divide by zero errors, so you could debate about anything you want (search the forums if you really want to see war ;))

yeah but i dont like war.. or nit picking for that matter ;) I just thought some general info on how to use trigonometry would do good.