Add 2 BIts to beginning of a Byte

I need to add two bits from one byte to the beginning of another 8 bit number. Example

Byte 1 Byte 2
00110011 11000100
11------>11000100 to get 1111000100

Plus this is happening at 300/second so the faster the better.

I've read about the bitarray() class but they don't have a way to get more than one value from the bit array at a time.

I also tried bitmasking the first 6 bits in byte one to get the last two bytes (which works) and then add them to byte2 but if I use the ampersan ("&") it just adds the value of the two bits to the value of the next 8 bits, Example:

11 (Value of 3) to 00000111(value of 7) = 37
not what I need
If I use the "+" operator it just add the two numbers 3+7 = 10

BUT I need the value for 1111000100 .

Sorry if this is confusing at all.....

Thanks,
Bebandit

There is a class called BitConverter. If I am not mistaken what you want is to get the decimal of 2 bytes ( which is Short data type). You can use this.....

BitConverter.ToInt16(bytes, 0)

where bytes consists of 2 bytes (or more) and byte1 and byte2 = 00110011 11000100.

The resulting could be different on different OS. you need to make sure that the byte is stored in certain order (LittleEndian/BigEndian), and do byte swapping when necessary.