In = Integral{1/(x2 + 2x + 2)n}dx (-1 to 0)
I'm pretty stuck with this one!
Apparantly the answer is:
2nIn+1 = (2n - 1)In + 2-n
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In = Integral{1/(x2 + 2x + 2)n}dx (-1 to 0)
I'm pretty stuck with this one!
Apparantly the answer is:
2nIn+1 = (2n - 1)In + 2-n