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I have a picture that is 100 pixels wide by 200 pixels high. This picture is going into a picture box and will then be rotated at various angles. What I need to be able to figure out is how big the picture box has to be as the picture rotates so I don’t chop any of it off.
assuming you're rotating about the center, wouldn't this be a classic application of pythagreans' therum?
(100^2 + 200^2)^.5 =223.60679774997896964091736687313
so, each side would need to accomodate 224 pixels. right?
What I'm really looking for is to keep the container only large enough to house the image. While the image may be able to fit within a square that is in the range of 225 square, that is a much larger area than I need when the image is either vertical or rotated 90 degrees.
Try this:
x = cos(rotation_angle)*height + sin(rotation_angle)*width
y = sin(rotation_angle)*height + cos(rotation_angle)*width
This should work. If it doesn't, let me know.