rounding with deciamals...

Is there a way to round the number 15.50193475 to 15.50 instead of 15.5?

Yes. Here's a code snippet from a project I did in school.

VB Code:

pdblAverage = ToDouble(pdblGrade1 + pdblGrade2 + pdblGrade3) / 3
psngAverage = System.Convert.ToSingle(pdblAverage)
lblAverage.Text = psngAverage.ToString("##.00")

its the ("##.00") at the end that dtermines how many decimals to extend the number to.

what will that do if i have a number that actually works like 15.645

It'll just turn it into 15.64. You want it to round to 15.65?

Quote:

---

Originally posted by Azkar
what will that do if i have a number that actually works like 15.645

---

Ancient chinese secret

Oh okay, i just want it to use a 0 for a place holder if its not 2 places after the decimal

After looking in the MSDN I found that this should work to round.

VB Code:

Round(15.50193475, 2)

That should return 15.50

If you use a variable:

VB Code:

dim MyNumber as double = 15.50193475
Round(MyNumber, 2)

I cant seem to find anything about actual rounding though. They always round to even. Like if its 16.345, it become 16.34 instead of 16.35.

<EDIT>

Right, the zeros are just placeholders.

Quote:

---

Originally posted by The Phoenix


I cant seem to find anything about actual rounding though. They always round to even. Like if its 16.345, it become 16.34 instead of 16.35.

---

If you're rounding to 2 decimal places, it will probably will only use those 2, so it just discards the 5

Maybe this thread helps, about rounding toward even.