Im pretty much stuck on this one. For some reason i cant' figure out how this equation should be factored. Thanks. :)
x - 2(x +3) = 6
x - 2x -6 = 6
x - 2x -12 = 0
As far as i get.........
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Im pretty much stuck on this one. For some reason i cant' figure out how this equation should be factored. Thanks. :)
x - 2(x +3) = 6
x - 2x -6 = 6
x - 2x -12 = 0
As far as i get.........
For instance some of these are quite easy.......
-m2 = 8 - 9m
0 = m2 -9m + 8
(m-8)(m-1)
m2 - m -8m + 8
m2 - 9m + 8
m = 8,1
from this point:Quote:
Originally posted by Dilenger4
Im pretty much stuck on this one. For some reason i cant' figure out how this equation should be factored. Thanks. :)
x - 2(x +3) = 6
x - 2x -6 = 6
x - 2x -12 = 0
As far as i get.........
x - 2x -12 = 0
==> -x -12 = 0
==> -12 = x
or, from right to left:
==> x = -12
is this what you need?
-Lou
If you ment x^2 -2x -12, then try completing the square.
x^2-2x=12
x^2-2x+2=14
(x-1)^2=14
x=(+/-)SQRT(14)+1
Yes exactly Lou :D I didn't think to solve that way. The whole chapter revolves around solving polynomial equations by factoring so i thought i was looking at the product of two binominals. Just as (m-8)(m-1) factored equals m2 -9m + 8.