checking file is open**resolved**

Hey everyone how are you doing.

Anyway how would i tell if a text file is already open. like if i have one program that write to the file and another program that does to. how would i be able to tell if it is open.
thanks for the help

well for one thing the second program would get an error trying to open it if its already open.. so if you trap the error using error handling.. that is one way you could tell

yeah that is the way i have it but i want to make the 2nd program to keep trying till it can open it. and i couldnt get that to work with trapping the error. i was hoping maybe there was another way to do it
and thanks for the reply

If u open that Document in Notepad for example, u can't see if the document is open... Notepad reads the Textfile in the memory and then directly closes the file again.

actually the program that is opening it jst has 2 buttons one to open and one to close this program is to test the other program. i want to be able to detect when another vbprogram has the file open and the second one wants to write to the text file.

anyone? please jst tell me if it is possible then tell how and if not jst say no its not possible. thank

Ok...

VB Code:

1
On error goto ErrSub:
open...
close...
 
msgbox "Opened"
exit sub
 
ErrSub:
Err.Clear
DoEvents ' so u don't freeze?
Goto 1

Good luck,

still giving me an error. it give me the error and i have no time to close the file.

well maybe its not possible
:mad: :(

Are you using freefile?

no im not i dont need to i dont think.

What's the error you're receiving?

Run-time Error 70:
Permission Denied

and i know it cause the file is already open too cause i have another program that is running and it has the file open. and i got all the permissions set to work for me cause that was a problem this morning.

Is there no way to check if a file is open. if there is please tell me if not then jst say "no there isnt". and i will drop this question. and try something else. thanks

Quote:

---

Originally posted by big_k105
Is there no way to check if a file is open. if there is please tell me if not then jst say "no there isnt". and i will drop this question. and try something else. thanks

---

When you open the file in either place, open it as #1.

then you can always tell if it is currently open with:

VB Code:

if FreeFile = 1 then
      'File is not open currently
Else
      'File is already open
end if

Of course this isnt the "normal" function of FreeFile, but you could take advantage of it in this way.

will that work if i open it in two completely different programs

Quote:

---

Originally posted by Muddy
When you open the file in either place, open it as #1.

then you can always tell if it is currently open with:

VB Code:

if FreeFile = 1 then
      'File is not open currently
Else
      'File is already open
end if

Of course this isnt the "normal" function of FreeFile, but you could take advantage of it in this way.

---

sorry ... scratch that ... I just realized you said it is a second app that has it open ...

ok, im i stuck using "On Error". i hope not but thats what its looking like.

and if i am stucking using that is there a way to specify to do something on a specified error and then do something else on a different error. if they are in the same sub.

Quote:

---

Originally posted by big_k105
ok, im i stuck using "On Error". i hope not but thats what its looking like.

and if i am stucking using that is there a way to specify to do something on a specified error and then do something else on a different error. if they are in the same sub.

---

I think trapping an error is the only way. Why not reduce it to an intuitive function though? ie

VB Code:

Public Function FileIsOpen(strFileName) As Boolean
    Dim i As Integer
    On Error GoTo errtrap
    FileIsOpen = False
    i = FreeFile
    Open strFileName For Input As #1
    Close #1
    Exit Function
errtrap:
    FileIsOpen = True
End Function

usage:

If FileIsOpen("C:\Test.txt") then
msgbox "it is open"
end if

thanks alot muddy. that worked great on the forum load.