List Control Column Widths

Hi and thanks for reading.

As with most things in VC++ (as it seems to me), something simple takes forever to figure out. :( Here's the deal. I have a list control with 3 columns. I want to size the columns based on the total width of the list control and not on hard-coded values. Here's my code:

Code:

---

        CRect                rListViewWidth;
        LV_COLUMN        listColumn;
        int                nColumn = 0;
        char*                arColumns[3] = {"One", "Two", "Three"};       

        // Set up the list control.
        listColumn.mask = LVCF_FMT|LVCF_WIDTH|LVCF_TEXT|LVCF_SUBITEM;
        listColumn.fmt = LVCFMT_LEFT;
        ::SendMessage(m_listCtrl.m_hWnd, LVM_SETEXTENDEDLISTVIEWSTYLE,
                                  LVS_EX_FULLROWSELECT, LVS_EX_FULLROWSELECT);

        m_listCtrl.GetWindowRect(&rListViewWidth);
        int nWidth = rListViewWidth.Width();

        // Add the column headers to the list view.
        for( nColumn = 0; nColumn < 3; nColumn++ )
        {
                listColumn.iSubItem = nColumn;
                listColumn.pszText = arColumns[nColumn];

                // Size the columns.
                if(nColumn == 0) // One
                        listColumn.cx = (nWidth * 20 / 100);
                else if(nColumn == 1) // Two
                        listColumn.cx = (nWidth * 37 / 100);
                else if(nColumn == 2) // Three
                        listColumn.cx = (nWidth * 42 / 100);

                m_listCtrl.InsertColumn(nColumn, &listColumn);
        }

---

I put in the (nWidth * x / 100) to avoid compiler warnings about converting from double to int. Anyway, I know this is simple, but I've already spent too much time trying to figure it out. Can someone tell me how to do this?

Thanks,

OneSource