Windows version numbers?

Does anyone know the equivalent version numbers for Windows NT 3 and 4?

I think the following is correct:

Win95 = 4.0
Win95b = 4.0b
Win98 = 4.10
Win98SE = 4.10a
WinME = 4.90
WinNT3 = ?
WinNT4 = ?
Win2K = 5.0
WinXP = 5.1

Any help would be appreciated.

Here's some code that returns the Windows version, it doesn't seem to relate fully to what you specified (only NT based versions link to the numbers you stated, and XP is different - but this part of the code may be wrong)

VB Code:

Private Declare Function GetVersionEx Lib "kernel32" Alias "GetVersionExA" (ByRef lpVersionInformation As OSVERSIONINFO) As Long
 
Private Type OSVERSIONINFO
    dwOSVersionInfoSize As Long
    dwMajorVersion As Long
    dwMinorVersion As Long
    dwBuildNumber As Long
    dwPlatformId As Long
    szCSDVersion As String * 128
End Type
 
Private Const VER_PLATFORM_WIN32s = 0
Private Const VER_PLATFORM_WIN32_WINDOWS = 1
Private Const VER_PLATFORM_WIN32_NT = 2
 
Private Function LoWord(lngIn As Long) As Integer
   If (lngIn And &HFFFF&) > &H7FFF Then
      LoWord = (lngIn And &HFFFF&) - &H10000
   Else
      LoWord = lngIn And &HFFFF&
   End If
End Function
 
Public Function WinVersion(Optional show_version As Boolean = True, _
                           Optional show_build As Boolean = True) As String
'Returns Windows version & build
 
Dim version As OSVERSIONINFO
Dim strPlatform As String
 
    version.dwOSVersionInfoSize = Len(version)
    GetVersionEx version
 
    If version.dwPlatformId = VER_PLATFORM_WIN32s Then
      strPlatform = "Microsoft Windows 32s "
 
    ElseIf version.dwPlatformId = VER_PLATFORM_WIN32_WINDOWS Then
      Select Case version.dwMinorVersion
      Case 0
              If LoWord(version.dwBuildNumber) = 1111 Then
                strPlatform = "Microsoft Windows 95B "
              Else
                'If LoWord(version.dwBuildNumber) = 950 Then
                strPlatform = "Microsoft Windows 95 "
              End If
      Case 10
              If LoWord(version.dwBuildNumber) = 2222 Then
                strPlatform = "Microsoft Windows 98 SE "
              Else
              'if LoWord(version.dwBuildNumber) = 1998 Then
                strPlatform = "Microsoft Windows 98 "
              End If
      Case 90
              'if LoWord(version.dwBuildNumber) = 3000 Then
              strPlatform = "Microsoft Windows ME "
      End Select
 
    ElseIf version.dwPlatformId = VER_PLATFORM_WIN32_NT Then
      Select Case version.dwMajorVersion
      Case 3:      strPlatform = "Microsoft Windows NT 3.51 "
      Case 5:      strPlatform = "Microsoft Windows 2000 "
      Case 6:      strPlatform = "Microsoft Windows XP "
      Case Else:   strPlatform = "Microsoft Windows NT "  '(was 4, best for any others!)
      End Select
    End If
 
    WinVersion = strPlatform _
               & IIf(show_version, "v" & Format(version.dwMajorVersion) & "." & Format(version.dwMinorVersion), "") _
               & IIf(show_build, " (Build " & LoWord(version.dwBuildNumber) & ")", "")
 
End Function

I think NT3 is 3.51.

Quote:

---

Originally posted by Sastraxi
I think NT3 is 3.51.

---

Agreed.

Regards,

Paul.