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Help! I just figured out I really suck at this.
How can I figure out x (in terms of the angles and other side of course)?
Also, it would be a great help if someone could point out a site to me that teaches this simple stuff.
Thanks. :(
http://www.vbforums.com/attachment.p...postid=1367425
is that 30 the angle on that side?
if so:
a triangle with 1 side as the diameter is always right. The bottom angle is the right angle. So this makes a 30 60 90 triangle. I don't remember the proportion for any sides...but I think it has sqrt(2) in it.:D
Using Trigonometry:
Given that AY = 15, so:
Y = 30,
X = unknown
if we use the relationship:
sin 30deg = x/30
x = 30 * sin 30deg
x = 15
assuming that c is a right angle, but its not given.
if ab crosses the circle center, then you could draw a line from it to c and show that it is though.
BTW:
sin(30) = 1/2
cos(30) = sqr(3)/2
tan(30) = 1/sqr(3)
Oh, the humiliation if i mixed up 30 and 60 again :D
Tan 30deg is sqrt(3)/3, not 1/sqrt(3).Quote:
Originally posted by sql_lall
BTW:
sin(30) = 1/2
cos(30) = sqr(3)/2
tan(30) = 1/sqr(3)
Oh, the humiliation if i mixed up 30 and 60 again :D
wait:
sqr(3)
-------
__3_______(Underlines for spacing reasons)
= 1 *sqr(3)
----------------
sqr(3)*sqr(3)
= 1
------
sqr(3)
Still, you were wrong,
denomonators must be rationalized, or it's invalid.
fine, fine
yet tan(30) is just an irrational number, and both 1/sqr(3) AND sqr(3)/3 are equal to that number :p
And, it's actually not 'invalid':mad: , just 'frowned upon' :( - ;)
nah its just that teachers like it more that way and they tend to "take marks off" in order to penalise you for not using a "good habit"Quote:
denomonators must be rationalized, or it's invalid.