Just Need A Simple Answer

I'm converting some C++ code to VB.

I don't understand how part of this declaration works:
#ifndef IGBOOL
#ifdef __WIN32
typedef int IGBOOL;
#else
typedef long IGBOOL;
#endif
#endif

struct NotifyCallbackRecord{
IGBOOL Message; /* The message ID for the notification */
IGBOOL DataStatus; /* The status of the data attached to the notification */
char Data; /* The address of the data attached to the notification */
};

The type IGBOOL is defined as an INT.

I understand that an INT in C++ equals a LONG in VB.

But how can a CHAR be an address?
Isn't a CHAR a single byte?

I need to convert this to VB.

Anyone? Anyone?

Never mind about the #if things. On 32 bit systems they don't matter.

char Data;
This however looks like a typo. Actually it should probably be
char *Data;
which is a pointer. The corresponding VB datatype is again Long, but you can't use pointers in VB unless you use the API.

Thanks, but I don't think it's a typo.

There are at least 5 other declarations, none of which have the "*".

Of course, I can't guarantee that the Sample code I copied this from works either, but I believe it will.

Then it could be some sort of index. You would have to look up its usage.