Just Need A Simple Explanation

I'm converting some C++ code to VB.

I don't understand how part of this declaration works:
#ifndef IGBOOL
#ifdef __WIN32
typedef int IGBOOL;
#else
typedef long IGBOOL;
#endif
#endif

struct NotifyCallbackRecord{
IGBOOL Message; /* The message ID for the notification */
IGBOOL DataStatus; /* The status of the data attached to the notification */
char Data; /* The address of the data attached to the notification */
};

The type IGBOOL is defined as an INT.

I understand that an INT in C++ equals a LONG in VB.

But how can a CHAR be an address?
Isn't a CHAR a single byte?

I need to convert this to VB.

Anyone? Anyone?

CHAR is a CHAR but a CHAR* is a pointer to a CHAR that can be a CHAR array pointer that is poiting to the first member of the array.
this can sound confusing....but it isn't lol

So, if a CHAR is just a sinlge byte char, then how could it be used as way of passing/pointing to an address?

More importantly, if I'm trying to re-write this in VB, how would it be done?

char* would be a pointer, but obviously its char here :p
otherways you could have an array of bytes

So how does that help me?