VB - Detect if you are running in the IDE...
VB Code:
Option Explicit
Private Declare Function GetModuleFileName Lib "kernel32" Alias "GetModuleFileNameA" (ByVal hModule As Long, _
ByVal lpFileName As String, _
ByVal nSize As Long) _
As Long
Private Declare Function GetModuleHandle Lib "kernel32" Alias "GetModuleHandleA" (ByVal lpModuleName As String) As Long
Private Function InIDE() As Boolean
Dim s As String
s = Space$(255)
Call GetModuleFileName(GetModuleHandle(vbNullString), s, Len(s))
InIDE = (UCase$(Trim$(s)) Like "*VB6.EXE*")
End Function
'usage
MsgBox InIDE
This is for VB6, for versions below 6, change the bolded section to the file name of the VB executable (VB5.exe, etc).
Re: VB - Detect if you are running in the IDE...
Here is another method (from vbAccelerator):
VB Code:
' modular level variable:
Private m_bInIDE As Boolean
Public Property Get InIDE() As Boolean
Debug.Assert (IsInIDE())
InIDE = m_bInIDE
End Property
Private Function IsInIDE() As Boolean
m_bInIDE = True
IsInIDE = m_bInIDE
End Function
I don't like static variables that much (don't ask why) so I think this method is somewhat cool. The only problem is that you need more lines of code.
Re: VB - Detect if you are running in the IDE...
hi,
you can do the same with
App.LogMode
Re: VB - Detect if you are running in the IDE...
I think you can like this, but i don't have vb with me to check:
VB Code:
Private Sub Command1_Click()
Dim mode
mode = App.LogMode
If mode = 0 Then
MsgBox "Running In IDE Version"
ElseIf mode = 1 Then
MsgBox "Running in Compiled Version"
End If
End Sub
Re: VB - Detect if you are running in the IDE...
since it's not been mentioned, here's another way:
VB Code:
Public InIDE As Boolean
Private Sub Main()
On Error Resume Next
Debug.Print 1 / 0
InIDE = Err.Number
End Sub
Re: VB - Detect if you are running in the IDE...
I like bushmobiles best, but I've always used:
' Declarations:
' In Form Load or Sub Main:
VB Code:
InIDE = False ' for clarity
Debug.Assert CheckForIDE ' set value of InIDE to true if in Dev Environment
' In form or module
VB Code:
Prublic Function CheckForIDE() As Boolean
' identifies app running in DEV environment
InIDE = True
CheckForIDE = True
End Function
Debug.Assert will only run in the IDE. Check InIDE for True = in IDE.
Re: VB - Detect if you are running in the IDE...
another way..
With no API declaration, no outside variable declaration, only a single function, tested in ActiveX DLL!
VB Code:
Public Function InIDE() As Boolean
Static i As Byte
i = i + 1
If i = 1 Then Debug.Assert Not InIDE()
InIDE = i = 0
i = 0
End Function
Re: VB - Detect if you are running in the IDE...
vb Code:
Public Function InIDE() As Boolean
InIDE = CBool(App.LogMode = 0)
End Function
Re: VB - Detect if you are running in the IDE...
Quote:
Originally Posted by
*PsyKE1*
vb Code:
Public Function InIDE() As Boolean
InIDE = CBool(App.LongMode = 0)
End Function
LogMode maybe? ;)
See post #5 & #6 above
Re: VB - Detect if you are running in the IDE...
xD Sorry men
I had not noticed
And yes, it should be : LogMode
Not LongMode! xD
Re: VB - Detect if you are running in the IDE...
I know this is a very old thread, but I like all the different approaches listed above.
Thought I'd add one more. This applies to usercontrols only
1) VB only. Not guaranteed to apply to other "IDEs": Word, Access, IE, etc
2) Your usercontrol is uncompiled and you want to know if whatever is hosting it is in design-view
Normally, we'd use Ambient.UserMode which would return False indicating the host is in design view, not run-time. However, while designing, let's say you create a second usercontrol (UC) that hosts the first UC. Everything is in design view, neither UC is compiled.
What's the problem? The 1st UC that's hosted in the 2nd UC will return Ambient.UserMode = True. This may be an issue if you are using that return value to start subclassing or API timers or something else that shouldn't be run in design view. UCs in design view are not guaranteed to get a Terminate event in design view; so subclassing, etc, should be handled carefully. You can test this by placing a debug.print statement in the control's Terminate event, then
1) On the form, right click on the form and choose menu: update controls. Debug.Prints show
2) Now open a UC code window & hit carriage return anywhere to force cross-hatching & close the UC
3) On the form, update controls again: No Debug.Prints show. Any subclassing may be crashing IDE
4) Compiled UCs get terminate events.
Solution. If you create a Private Sub Main(), in a bas module, and set your UC to start with Sub Main via the UC properties dialog, then you can use that to your advantage. Add a public boolean variable to that module and in Sub Main() set that variable to True. Where you were testing for Ambient.UserMode, now test for that public boolean's value instead.
While the UC is uncompiled and host is in design view, VB does not call the Sub Main() of the UC, but the Ambient.UserMode can change as described earlier.
Simple example
1) Start a new project (exe type)
2) Click on IDE menu: File | Add Project. This will create a group project
3) Choose Active-X Control project
4) In that Active-X project, add 1 module, set the UC's AutoRedraw to True
5) In the module, paste this code
Code:
Public g_UserMode As Boolean
Private Sub Main()
g_UserMode = True
End Sub
6) In the UC add this in the Show event
Code:
Print "Ambient.UserMode = "; Ambient.UserMode
Print "g_UserMode "; g_UserMode
7) In the UC's properties, set the startup to Sub Main. IDE Menu: Project | Project2 Properties
8) Close all the UC windows opened in design view
9) Place the UC on the form. You should see that the printed lines return the same value, both in design view & run-time
When done playing, return to IDE and close all windows. Then
1) Add 1 more project to the group and make it an Active-X Control also
2) Change the control's name in the property sheet from UserControl1 to UserControl2
3) In that new UC, draw the 1st UC in it and close all IDE windows
4) Open the form in design view and draw the 2nd UC on the form
You will notice the 2 UC's display different Ambient.UserMode values in design time, but the same in run time
Re: VB - Detect if you are running in the IDE...
similar to Post#1
Code:
Public Declare Function InIDE Lib "kernel32" Alias "GetModuleHandleA" (Optional ByVal lpModuleName As String = "vba6.dll") As Long
Re: VB - Detect if you are running in the IDE...
I know this thread is old but I have run the various techniques for determining whether the code is executing in the IDE or in a compiled form. In each case I put the code into a function that returned True if the code was executing in the IDE and False otherwise. The times below are the number of milliseconds required for each function to run 100 million times.
Code:
Un-compiled Compiled
vbAdvance "In_IDE" conditional compilation command 4,510 ms 196 ms
Using Debug.Assert (similar to post #4) 10,490 196
Using App.Log (see posts #5 & 6) 12,807 10,340
Debug.Print a /0 (see post #7) 42,520 7,330
Look for IDE window (see post #16) 478,000 49,600
The above techniques are all based on doing something in the IDE that doesn't exist in the compiled code. The vbAdvance method overrides a compilation constant at compile time. The others use Debug.Assert, Debug.Print and App.LogMode. It shouldn't be a surprise that those in the IDE run are slower in the checking code because 1) compiled code runs faster and 2) the code that doesn't exist in compiled mode such as Debug.Print does exists in the IDE and it takes time to run.
If for no other reason than visual styles, most of us start with Sub Main and we have general initialization code there where we can determine whether we are in the IDE or not and then save that setting for later checking. I use the 2nd technique because I don't have to set a compilation constant and because it performs just as fast in compiled code as technique #1. I do use vbAdvance for a lot of things, just not this.
Re: VB - Detect if you are running in the IDE...
Another one:
Code:
'in a module
Public gIde As Boolean
Private Declare Function GetCurrentProcessId Lib "kernel32" () As Long
Private Declare Function GetWindowThreadProcessId Lib "user32" (ByVal lhWnd As Long, lProcessId As Long) As Long
Private Sub Main()
Dim x As Long
GetWindowThreadProcessId FindWindowA("IDEOwner", vbNullString), x 'search for VB6 IDE window and get process identifier
gIde = (GetCurrentProcessId = x)
End Sub
Re: VB - Detect if you are running in the IDE...
i have a test of the above method, should be all of them.
VB Code:
'modIDE.bas
Private m_bInIDE As Boolean ' module level variable:
Public Declare Function InIDE8 Lib "kernel32" Alias "GetModuleHandleA" (Optional ByVal lpModuleName As String = "vba6.dll") As Long
Private Declare Function GetModuleFileNameA& Lib "kernel32" (ByVal hModule&, ByVal lpFileName$, ByVal nSize&)
Private Declare Function GetModuleHandleA& Lib "kernel32" (ByVal lpModuleName$)
Private Declare Function GetCurrentProcessId Lib "kernel32" () As Long
Private Declare Function GetWindowThreadProcessId Lib "user32" (ByVal lhWnd As Long, lProcessId As Long) As Long
Private Declare Function FindWindowA Lib "user32.dll" (ByVal lpClassName As String, ByVal lpWindowName As String) As Long
Public Function InIDE1() As Boolean
Dim s As String
s = Space$(255)
Call GetModuleFileNameA(GetModuleHandleA(vbNullString), s, Len(s))
InIDE1 = (UCase$(Trim$(s)) Like "*VB6.EXE*")
End Function
Public Function InIDE2() As Boolean
Static counter As Variant
If IsEmpty(counter) Then
counter = 1
Debug.Assert InIDE2() Or True
counter = counter - 1
ElseIf counter = 1 Then
counter = 0
End If
InIDE2 = counter
End Function
Public Property Get InIDE3() As Boolean
Debug.Assert (IsInIDE())
InIDE3 = m_bInIDE
End Property
Private Function IsInIDE() As Boolean
m_bInIDE = True
IsInIDE = m_bInIDE
End Function
Public Function InIDE4() As Boolean
On Error Resume Next
Debug.Print 1 / 0
InIDE4 = Err.Number
End Function
Public Function InIDE5() As Boolean
Static i As Byte
i = i + 1
If i = 1 Then Debug.Assert Not InIDE5()
InIDE5 = i = 0
i = 0
End Function
Public Function InIDE6() As Boolean
InIDE6 = CBool(App.LogMode = 0)
End Function
Public Function InIDE7() As Boolean
Dim x As Long
GetWindowThreadProcessId FindWindowA("IDEOwner", vbNullString), x 'search for VB6 IDE window and get process identifier
InIDE7 = (GetCurrentProcessId = x)
End Function
VB Code:
'frmIDE.frm
Private Sub Form_Load()
Me.AutoRedraw = True
testIDE
End Sub
Sub testIDE()
Dim i&, bool As Boolean
Const n As Long = 1000
mTimer = 0
For i = 1 To n
bool = InIDE1
Next i
Print 1 & vbTab & bool & vbTab & Round(mTimer, 3)
mTimer = 0
For i = 1 To n
bool = InIDE2
Next i
Print 2 & vbTab & bool & vbTab & Round(mTimer, 3)
mTimer = 0
For i = 1 To n
bool = InIDE3
Next i
Print 3 & vbTab & bool & vbTab & Round(mTimer, 3)
mTimer = 0
For i = 1 To n
bool = InIDE4
Next i
Print 4 & vbTab & bool & vbTab & Round(mTimer, 3)
mTimer = 0
For i = 1 To n
bool = InIDE5
Next i
Print 5 & vbTab & bool & vbTab & Round(mTimer, 3)
mTimer = 0
For i = 1 To n
bool = InIDE6
Next i
Print 6 & vbTab & bool & vbTab & Round(mTimer, 3)
For i = 1 To n
bool = InIDE7
Next i
Print 7 & vbTab & bool & vbTab & Round(mTimer, 3)
For i = 1 To n
bool = InIDE8
Next i
Print 8 & vbTab & bool & vbTab & Round(mTimer, 3)
End Sub
VB Code:
'modTiming
Option Explicit
Private Declare Function QueryPerformanceCounter Lib "kernel32" (x As Currency) As Boolean
Private Declare Function QueryPerformanceFrequency Lib "kernel32" (x As Currency) As Boolean
Dim m_Time As Double '
Dim m_TimeStart As Currency
Dim curFreq As Currency
Dim m_TimeFreq As Double
Public Property Get mTimer() As Double
Dim curTime As Currency
QueryPerformanceCounter curTime
'Debug.Print curTime; m_TimeStart
mTimer = 1000 * (curTime - m_TimeStart) * m_TimeFreq + m_Time 'minisections
End Property
Public Property Let mTimer(ByVal newValue As Double)
Dim curOverhead As Currency
m_Time = newValue
QueryPerformanceFrequency curFreq
m_TimeFreq = 1 / curFreq
QueryPerformanceCounter curOverhead
QueryPerformanceCounter m_TimeStart
m_TimeStart = m_TimeStart + (m_TimeStart - curOverhead)
End Property
Code:
i have test 3 options in my computer:
1st: InIDE
1 True 18.83
2 True .452
3 True .378
4 True 2.029
5 True .587
6 True .523
7 True 40.376
8 True 42.668
2nd: InEXE with "Advanced optimization"
1 False 9.936
2 False .262
3 False .006
4 False .287
5 False .007
6 False .438
7 False 38.77
8 False 40.839
3rd: InEXE without "Advanced optimization"
1 False 15.369
2 False .3
3 False .007
4 False .32
5 False .023
6 False .505
7 False 52.38
8 False 54.775
it seems in my computer InIDE3 is the best option.
Re: VB - Detect if you are running in the IDE...
Performance is not really an issue when you cache the result in a global/local variable.
Set it at the start up of the application and then you only have a single boolean variable.
Re: VB - Detect if you are running in the IDE...
InIDE3 FTW!
You can even remove the "global" m_bInIDE altogether like this
thinBasic Code:
Public Property Get InIde() As Boolean
Debug.Assert pvSetTrue(InIde)
End Property
Private Function pvSetTrue(bValue As Boolean) As Boolean
bValue = True
pvSetTrue = True
End Function
cheers,
</wqw>
Re: VB - Detect if you are running in the IDE...
I agree with Arnoutdv: it doesn't matter the method, you need to store the result in a valriable. I usually use a Static variable.
Code:
Public Function InIDE() As Boolean
Static sValue As Long
If sValue = 0 Then
Err.Clear
On Error Resume Next
Debug.Print 1 / 0
If Err.Number Then
sValue = 1
Else
sValue = 2
End If
Err.Clear
End If
InIDE = (sValue = 1)
End Function
Re: VB - Detect if you are running in the IDE...
This is the one I currently use:
Code:
Public Function InIDE(Optional ByRef b As Boolean = True) As Boolean
' NEVER specify the Optional b when calling.
If b = True Then Debug.Assert Not InIDE(InIDE) Else b = True
End Function
It was inspired by something I saw The Trick do. It's nice in that no disk I/O is performed. And it's very fast and terse. Also, it won't tamper with the Err object. I've used maybe half-a-dozen through the years, and I think the above is best.
EDIT1: I suppose you could add a Static to it to make it slightly faster, but it's pretty fast as it is. I'll let loquat test if he likes. :)
Re: VB - Detect if you are running in the IDE...
Prior art:
Quote:
Originally Posted by
Bonnie West
Code:
Private Function InIDE(Optional ByRef B As Boolean = True) As Boolean 'Very efficient function for testing whether
If B Then Debug.Assert Not InIDE(InIDE) Else B = True 'this code is running in the IDE or compiled
End Function 'Based on the original by Vesa Piittinen
Re: VB - Detect if you are running in the IDE...
You cannot make InIDE3 faster by adding a static as the single Debug.Assert eventually gets removed, so in compiled executable it gets reduced to a no-code function w/ no parameters.
The only way to beat this is if you don't call anything at all I suppose :-))
cheers,
</wqw>
1 Attachment(s)
Re: VB - Detect if you are running in the IDE...
Quote:
Originally Posted by
wqweto
You cannot make InIDE3 faster by adding a static as the single Debug.Assert eventually gets removed, so in compiled executable it gets reduced to a no-code function w/ no parameters.
The only way to beat this is if you don't call anything at all I suppose :-))
cheers,
</wqw>
Compiled yours and Elroy's one are quite faster than mine.
Compiled, 100,000,000 iterations:
Code:
InIDE3 0.101
mine 2.226
Elroy's 0.156
global variable 0.046
Uncompiled, 100,000,000 iterations:
Code:
InIDE3 8.031
mine 4.789
Elroy's 8.304
global variable 0.507
But if speed is really an issue, the best (of course) is to use just a variable and set it up when the program starts.
PS: I didn't test others.