Resolved - Evaluate the first 4 characters in a string?

How can I do this?

Let's say the string..

Code:

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var strString = "12.This is it"

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How can I test if the first 2 chars are numbers and then there is a [.] after it?

Thanks

I'd use regular expressions (Javascript in newer browsers has Perl style RegEx syntax, same as VBScript).

Code:

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if ( /^\d{2}\./.test(strString) ) {

}

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Quote:

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Originally posted by JoshT
I'd use regular expressions (Javascript in newer browsers has Perl style RegEx syntax, same as VBScript).

Code:

---

if ( /^\d{2}\./.test(strString) ) {

}

---

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I appreciate that. But the strings will not always be the same. It will be like this:

1.sdfsddsfsdf
2.dfsdfsdfdsf
3.sdfsdf

etc...

Thanks

Why is the code still finding a match for the [.] when it is not in the string?

Code:

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<SCRIPT LANGUAGE=javascript>
<!--
        var strString = "12this is it"
        if ( /^\d|\d\./.test(strString) ) {
                alert(strString)
        }

//-->
</SCRIPT>

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How can I look for either occurence of 12 or 1 in the string?
Because so far only will find 2 occurences first.

Code:

---

<SCRIPT LANGUAGE=javascript>
<!--
        // / beginning and end of what is evaluated
        // \d = [0-9]
        // \s =  space
        // \ separator
       
        var strString = "1. this is it"
        if ( /^\d|\d\.\s/.test(strString) ) {
                alert(strString)
        }

//-->
</SCRIPT>

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NEver mind , got it!

Code:

---

<SCRIPT LANGUAGE=javascript>
<!--
        // / beginning and end of what is evaluated
        // \d = [0-9]
        // \s =  space
        // \ separator
       
        var strString = "12. this is it"
        if ( /^\d{1,2}\.\s/.test(strString) ) {
                alert(strString)
        }

//-->
</SCRIPT>

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He he, I love it when people answer their own posts ;)