need help with this program.

Quote:

---

#include <iostream.h>
int num1,num2;
int acc=1000;
char atm;
char keepon='y'||'Y';
;
void main ()

{

while (keepon=='y'||'Y')
{
cout <<"1. Make a deposit (Press D\n"
<<"2. Widthraw money (Press W)\n"
<<"3. See account info (Press A)\n"
<<"4. Exit Program (Press E)"<<endl;
cin >> atm;

switch (atm)
{
case 'D':
cout <<"Enter amount you want to despoit" <<endl;
cin >> num1;
cout <<"You have a total of " <<num1+acc <<" in your account"<<endl;
cout << "To continue enter Y" <<endl;
cin >> keepon;
break;
case 'W':
cout <<"Enter amount you want to widthraw" <<endl;
cin >> num1;
cout <<"You have a total of " <<acc-num1 <<" in your account"<<endl;
cout << "To continue enter Y" <<endl;
cin >> keepon;
break;
case 'A':
cout <<"Your Account info" <<endl;
cout << "To continue enter Y" <<endl;
cin >> keepon;
break;
case 'E':
cout <<"Goodbye. Have a nice day!" <<endl;
break;
default:
cout <<"\nInvalid operation";
break;
}
}
}

---

ok this is what i wrote. what i am trouble is that how do I get the balance to roll over?
Like after I press D and deposit $200 I have a total balance of $1200 (everyone start with $1000 balance). then I ask if you want to continue. press y for yes, and bring to the main menu, next I press W for widthraw. but when I widthraw like $500. it widthdraw from the balance of $1000 not my prevous balance, which is $1200. anyone could help me with this?

Think about it, it really isn't that hard...
When making a deposit or withdrawal and you show the result you add or subtract to the acc variable. But when doing it on the cout line you don't actually change the variable so you would have to have num1+acc or acc-num2 on a seperate line.

but that is only good for 2 times tho. i have a loop, and if the person want to despoist 100 times, is should be able to allow them to do that. since you are saying i could just do "num1+acc or acc-num2 " then they only can do it for like 2 desposit right?

Wrong, you misunderstood him. He meant that instead of

Code:

---

case 'D':
  cout <<"Enter amount you want to despoit" <<endl;
  cin >> num1;
  cout <<"You have a total of " <<num1+acc <<" in your account"<<endl;

---

you should write

Code:

---

case 'D':
  cout <<"Enter amount you want to despoit" <<endl;
  cin >> num1;
  acc = num1+acc;
  cout <<"You have a total of " <<acc <<" in your account"<<endl;

---

or even better instead of
acc = num1 + acc;
write
acc += num1;

And write
#include <iostream>
using namespace std;

instead of
#include <iostream.h>

The .h header is deprecated and does not follow the newest C++ standard.

Finally, use [code] tags instead of [quote] tags, they preserve formatting like indentation, which makes the code easier to read.

thanks cornedbee, you answer my thread while i was at school. at that time I already figure it out myself..

i can't recall but I believe i did the same thing you said on the post..
my school uses borland 5.5 I guess its very old since I was told to use #include <iostream.h>


Anyway. Now its the most difficult part. when I press A, its suppose to display the account info. what my teacher mean is that display the history transaction. Like all the widtdraw and deposit that was made. Now this i really have no clue on how to even do this. could you please help me on this one?

And whats the cin command to exit the program? its for the Case E.

I'm affraid I can't help you with the history transactions stuff but I think I can help with ending the program.
Your loop begins with saying "while (keepon=='y'||'Y')" so I would assume that you just have to change the keepon value to something that is not y or Y (i.e. n or N for No). What the "cin >> keepon;" line does is it puts what ever character the user types in the variable keepon, you can do that in code useing the = operator, but I guess you already knew that... So your code should probably look something like this:

Code:

---

case 'E':
cout <<"Goodbye. Have a nice day!" <<endl;
keepon = 'n';
break;

---

McCain is right.

The transaction history is easy too. I would recommend a ostringstream from the header <sstream>, but since you have to use an outdated compiler (you should complain) you will have to use a ostrstream from <strstream.h>. This works like cout, but it saves everything into a string instead of writing it out.
Don't use endl, use '\n' instead.
Like this:

Code:

---

#include <strstream.h>
//...
ostrstream log;
log << "Original total: " << acc << '\n';
// ...
case 'D':
  cout <<"Enter amount you want to despoit" <<endl;
  cin >> num1;
  acc += num1;
  cout <<"You have a total of " <<acc <<" in your account"<<endl;
  log << "Deposition: " << num1 << '\n';
  log << "New total: " << acc << '\n';
// etc.

// output:
case 'A':
  cout << log.str() << endl;

---

To clear the history you could write:
log.str("");

we never learned "log.str("");" and we suppose to use stuff we learn. so that might even hold against me when it comes to grading the project.

Thats fair enough and you should use what you learn to show that you've taken it in. However, in this instance (and the other times you ask questions on here) you have been given a good solution.

I finished my degree some time ago and have been working in a software company. They don't care (within reason) what you do as long as it gets done. Therefore, in terms of your grades - if they tell you specifically to do something then do it - otherwise improvise. They can't take you down for doing something they didn't restrict.

On the other hand, if they told you to implement this in a particular way, then you've got to do it.

Just a couple of thoughts from someone who's done it before.

HD

raz0r - my normal disclaimer applies here. If your teachers have a problem with something that has been said here, they're welcome to come and attempt to fight it out with us.

Although unless they really want to prove just how crap they are, they're best getting a good book and learning how to do it themselves first.

They would first have to survive our attack for using an outdated compiler. That's hard enough if you're not immortal.