Initialising arrays of objects

Me again.

When you create an array of objects, how can you pass the arguments required by the constructor?

example:

when you declare a single object it might look something like this:

Code:

---

clsComplex Number(2,1);

---

but when you declare an array of objects:

Code:

---

clsComplex Number[3];

---

How do you also add the arguments for the constructors?

You cannot do it that way.

You have to allocate You objects at run-time (on heap) through new:

Code:

---

clsComplex* ppComplex[3];
for (int x=0; x < 3;++x)
{
        ppComplex[x] = new clsComplex(2,1); // call ctor with arguments
}

---

Don't forget to delete Your array-ptrs. after use!

Mikey ;)

I don't know, it should be possible:

Code:

---

object blah[3] = { object(4,5), object(2, 89), object(69, 31337) };

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Both work. Thanks muchly

Note that the first is more flexible, while the second is more efficient (and you don't need to delete afterwards).

Just as an addition, since it's kind of related:

What's up with this:

Code:

---

BYTE bArray[5];

bArray={1,2,3,4,5};

---

I can't use this "BYTE bArray[5]={1,2,3,4,5};" because the array values will changes.

Just to be specific, the code should assign 1 to bArray[0], 2 to bArray[1] etc.

You can use the second one, since you can still change the array contents.

It's only impossible to change it if you declare the array as const.

parksie is right,
You only need the new-op. if You have to decide at runtime, how large Your array is
or if You have to change the array-size.

Mikey

errr, how?

(I know I'm a pain)

what You mean - "how"?

if You mean with "how", how to assign new values to Your array:

Code:

---

BYTE bArray[5] = {1,2,3,4,5};

bArray[3] = 6; // assign a new value to index 3

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I was replying to parksie's , sorry

I wanted to know how I could change the contents of the array using the method you both describe.