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"thisline" refuses to add, i can't figure out whyPHP Code:$result = mysql_query("SELECT * FROM gallery WHERE id=$id");
while($row=mysql_fetch_array($result)){
$numvotes = $row['numvotes'] + 1;
$newrating = $row['rating'] + (int)rating;//thisline
$newrating /= $numvotes;
echo "$numvotes $newrating $rating $row[rating] <br>";
}
rating is passed through GET. $row[numvotes] + 1 adds fine
i tried casting it, thinking that would solve it, doesnt work either :(
Wait...
I'm not understanding the (int)rating thing. Should it be (int)$rating?
:confused:
I'm thinking just plain old $rating should do it. .... but then I'm not sure where rating came from either....Quote:
Originally posted by The Hobo
Wait...
I'm not understanding the (int)rating thing. Should it be (int)$rating?
:confused:
:confused:
I tried plain old $rating, didn't work
It's from GET:
$request = $_GET['request'];
I thought that maybe it wasn't adding because it can't add an int/string together, so you had to cast it to int. Or maybe that's just in C++
that's just C++.
hmm...I don't see how rating would work by itself. I thought you'd need to have $ infront of it to signify it's a variable. Does it give you any errors?
Try this:
Just to see if the last line isn't causing it. Debug it as much as possible, follow it through, and see where it gets you. That's about all I can suggest. :(Code:$newrating = $row['rating'] + $rating;
echo "newrating = $newrating<br>"; //for testing
$newrating /= $numvotes;
hahaha i am an idiot. it didnt work because i didnt put a $ in front of rating. Jeebus :p
Didn't we mention that up there? :pQuote:
Originally posted by nabeels786
hahaha i am an idiot. it didnt work because i didnt put a $ in front of rating. Jeebus :p
yes, i read that :p