Could someone lend a hand in solving (x+3)(x-2)>=0 algebraically. Thanks for any help!
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Could someone lend a hand in solving (x+3)(x-2)>=0 algebraically. Thanks for any help!
Ok, not really the most algebraic, but here goes:
interecepts: x = -3 and x = 2
graph concave (x^2 coefficient positive)
=> (x+3)(x-2)>=0 when x <= -3 or x >= 2
No i knew how to do that. I call that graphically. If anyone could help me algebraically? Thanx anyways sql_lall.
(x+3)(x-2)>=0
[(x+3)>=0 Intersection (x-2)>=0] U (union) [(x+3)<=0 Intersection (x-2)<=0]
you can take it from here
If two numbers multiply to a non-negative number, they cannot have opposite signs. x+3>x-2 ALWAYS, from which follows:
x-2>=0 or x+3<=0
x>=2 or x<=-3