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How can i turn this "name" into these HEZ numbers ??
Beta User = 1AC78 - 23D1B - 83EAD - A21B9
All i know is that the "name" part cannot be bigger
than 64 letters..
And That the HEX rows comes in 5 and five...
----
Is there an easy way to figure this out?
Can anyone make an app that does this
and if you write in something else like "kebab" then
it will output another
hex row like xxxxx-xxxxx-xxxxx-xxxxx
----
ASCii converted directly to hex is two characters.
Thus ASCii is base 256 technically.
Hex is base 16, but as two characters can represent 256 values.
There is no seemingly known correlation between the letters and the code.Quote:
Originally posted by alexdata
How can i turn this "name" into these HEZ numbers ??
Beta User = 1AC78 - 23D1B - 83EAD - A21B9
All i know is that the "name" part cannot be bigger
than 64 letters..
And That the HEX rows comes in 5 and five...
----
Is there an easy way to figure this out?
Can anyone make an app that does this
and if you write in something else like "kebab" then
it will output another
hex row like xxxxx-xxxxx-xxxxx-xxxxx
----
It's most likely a hash you seek.
For example 1A is 26, B is 66. Which could be acheived by xoring 88.
But can you explain me this?
HEX system thing:
0123456789abcdef
------------------------
ff = 256
00 = 0
-------------------------
but how do i get this?
1a = 26
How do i get that ,and what does 2a equal..
PS: You were rigth...the letters(name) had nothing to do with it..
Its ONLY the different numbers in the xxxxx-xxxxx.....
that has to do with it.
But what do you mean by XOR 88 ??
Can you make a small app that creates random strings that
is similat to the 1AC78 - 23D1B - 83EAD - A21B9 string??
bu that i mean that you have an app that uses XOR 88...
Thanks for all help so far!
Im really dying to learn this!
In hex:
0 = 0
1 = 1
etc.
A = 10
B = 11
C = 12
D = 13
E = 14
F = 15
15-0+1=16, so there are 16 different symbols to represent numbers.
Thus why it's called base 16, our standard decimal system is base 10, thus 0 through 9 9-0+1 = 10. now for base operations:
let b be the base number.(0-9)(0-F)
f=15
so 16 will be 10 thus: the first number is left alone(from the right, this is known as endian)
the cba the b is multiplied by 16 ^ 1
(the a is multipled by 16^0, which is 1, so there's no point
iterating it)
The c is multiple by 16 ^ 2, and so on if D existed, then *16^3, E, *16^4
Each spot over you take it to one higher power, you are effecting moving up from the base. Thus, you are exploiting the number system.
Now that you have all the results from each base digit, you add them together. In base 10 then is done seemlessly. As the numbers are multiple *10^x power, and their addition is the same as their base counterpart.
Like they say, there are 10 types of people, those who can read binary and those who cannot.
Can anyone make a prog that creates more keys
similar to this one by XOR 88 ???
1AC78 23D1B 83EAD A21B9
Is there anyone out there that can show me how?
Give an examle app or source for creating such a ke as the above!
In hex:
0=0
1=1
2=2
3=3
4=4
5=5
6=6
7=7
8=8
9=9
A=10
B=11
C=12
D=13
E=14
F=15
10=16
11=17
12=18
13=19
14=20
15=21
16=22
17=23
18=24
19=25
1A=26
1B=27
1C=28
1D=29
1E=30
1F=31
20=32
30=48
40=64
50=80
60=96
70=112
80=128
90=144
A0=160
B0=176
C0=192
D0=208
E0=224
F0=240
F1=241
F2=242
F3=243
F4=244
F5=245
F6=246
F7=247
F8=248
F9=249
FA=250
FB=251
FC=252
FD=253
FE=254
FF=255
thus:
the first number is the value*16+the second
if three hex values are there then then first is *16*16
or 16 to the power of 2
the powers start from 0 starting on the right
if take
WXYZ for example
z*16^0
+
Y*16^1
+
X*16^2
+
W*16^3
Before this thread goes any further, check out this cross post.
http://vbforums.com/showthread.php?s=&threadid=211830
:mad: