how to detect an already open form

I have probably a relatively simple question... (at least one would think)

IN my menu, there is an item that opens a form. I would like to put some code so that, if the user clicks it twice, instead of opening two forms, the already open form is just selected and brought to the front of everything. Does anyone have any suggestions? This is the menu code

VB Code:

Dim SegmentInfoForm As New frmSegmentInfo()
        SegmentInfoForm.Show()
        System.Windows.Forms.Application.DoEvents()

Thanks,

jkw119

VB Code:

'In the general declarations
Dim booFormLoaded as Boolean = False
 
'In your sub
If booFormLoaded = False then
        Dim SegmentInfoForm As New frmSegmentInfo
        SegmentInfoForm.Show()
        System.Windows.Forms.Application.DoEvents
        booFormLoaded = True
Else
        SegmentInfoForm.Focus()
End If

gL,
Furry

Try this

' defined in a module
public SegmentInfoForm As frmSegmentInfo()



In the click menu event :

if SegmentInfoForm is nothing or segmentinform.isdispose() then
SegmentInfoForm = new frmSegmentInfo()
endif
SegmentInfoForm.show()
SegmentInfoForm.topmost =true

[/code]
Private Sub MenuItem2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MenuItem2.Click, CmnuDisplayChild.Click
'Instantiate a child

LoadForm("frmChild")
End Sub

Private Sub LoadForm(ByVal strFormName As String)
'Load form or activate if it already exists
Dim frmForms() As Form = Me.MdiChildren
Dim intIndex As Integer
Dim blnFound As Boolean

'Does it exist?
For intIndex = 0 To frmForms.GetLength(0) - 1
If frmForms(intIndex).Name = strFormName Then
blnFound = True
frmForms(intIndex).Activate()
End If
Next

If Not blnFound Then
Select Case strFormName
Case "frmChild"
Dim frmChild As New ChildForm()
With frmChild
.MdiParent = Me
.Name = "frmChild"
.Show()
End With
End Select
Me.LayoutMdi(MdiLayout.Cascade)
End If
End Sub
[/code]