Could anybody maybe just give me a hint as to where to start for this question?
http://www.vbforums.com/attachment.p...postid=1249373
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Could anybody maybe just give me a hint as to where to start for this question?
http://www.vbforums.com/attachment.p...postid=1249373
let box=x^2-10x-45
And if that fails, multiply every fraction by:Quote:
Originally posted by bugzpodder
let box=x^2-10x-45
http://www.vbforums.com/attachment.p...postid=1249416
lol. anywayz, if we just use y=x^2-10x-45
we have:
1/(y+16)+1/y=2/(y-24)
multiply BS by (y+16)y(y-24)
y^2-24y+y^2-8y-16*24=2(y^2+16y)
2*y^2-32y-16*24=2y^2+32y
-64y=16*24
-4y=24
y=-6
x^2-10x-45=-6
x^2-10x-39=0
(x-13)(x+3)=0
x=13 or -3
I think it's a little bit easier if you let
y = x2 - 10x - 37
Then:
1 / (y + 8) + 1 / (y - 8) = 2 / (y - 32)
(y - 8 + y + 8) / (y2 - 64) = 2 / (y - 32)
y / (y2 - 64) = 1 / (y - 32)
y(y - 32) = y2 - 64
y2 - 32y = y2 - 64
So, y=2 and:
x2 - 10x - 37 = 2
x2 - 10x - 39 = 0
And solving for x you get the same values, x = 13 and x = -3