Take part of all lines in a text box

I have several lines that are like this:

5:16pm up 9 min(s), 1 user, load average: 0.03, 0.06, 0.04
6:16pm up 9 min(s), 2 user, load average: 0.03, 0.06, 0.04
7:16pm up 9 min(s), 3 user, load average: 0.03, 0.06, 0.04

I just what this part of the line(0.03, 0.06, 0.04)

Anyone has an idea? I don´t!

if you now every line of "5:16pm up 9 min(s), 1 user, load average:" then you could use the VB Replace function
to replace 5:16pm up 9 min(s), 1 user, load average: with " "

Assuming that there is a CR/LF pair at the end of each line, you could always do something simple like:

VB Code:

Temp1 = Mid(Text1, 43)
    MsgBox Left(Temp1, 16)
    
    Temp2 = Mid(Temp1, 43 + 16 + 2)
    MsgBox Left(Temp2, 16)
    
    Temp3 = Mid(Temp2, 43 + 16 + 2)
    MsgBox Left(Temp3, 16)

If you don't like the hard-coded numbers, do a locate for the words "average:" for the starting point, and VBCrLf for the end point.

Sorry but the number Cr/LF isn´t always pair, anyone has more ideas?

You need to code something like the following algorithm, based around the colons in the string:

Code:

---

String = YourTextBoxString

LOOP, while String Length > 16
  NewString = String, starting at the location of ":" + 1
  IF 1st character of NewString is a space THEN
        UseFullString = Next 16 characters from NewString
  END IF
  String = NewString, starting at location 17
END LOOP

---

VB Code:

Private Function ReturnLastDigitsOfLine(ByVal strWholeLine As String)
    
    Dim intChrCounter As Integer
    ReturnLastDigitsOfLine = ""
    
    For intChrCounter = 1 To Len(strWholeLine)
    
        If Not IsNumeric(Mid(Right(strWholeLine, intChrCounter), 1, 1)) Then
        
            If Not ((Mid(Right(strWholeLine, intChrCounter), 1, 1)) = "," Or _
            (Mid(Right(strWholeLine, intChrCounter), 1, 1)) = "." Or _
            (Mid(Right(strWholeLine, intChrCounter), 1, 1)) = " ") Then
            
                ReturnLastDigitsOfLine = Trim(Right(strWholeLine, intChrCounter - 1))
                Exit For
                
            End If
        
        End If
    
    Next intChrCounter
    
End Function

Usage:

VB Code:

Private Sub Form_Load()
    Dim strTemp As String
    strTemp = "5:16pm up 9 min(s), 1 user, load average: 0.03, 0.06, 0.04"
    
    MsgBox ReturnLastDigitsOfLine(strTemp)
End Sub

But that only gets the last bit of the string, rather than each item as it appears....

I understand that the string in the text box looks like this:

Code:

---

    Text1 = "5:16pm up 9 min(s), 1 user, load average: 0.03, 0.06, 0.04" & vbCrLf & _
"6:16pm up 9 min(s), 2 user, load average: 0.03, 0.06, 0.05" & vbCrLf & _
"7:16pm up 9 min(s), 3 user, load average: 0.03, 0.06, 0.06"

---

and so this code will process that string, displaying the end of each line in the message box. It decodes the string based on the ":"

VB Code:

strString = Text1
    While Len(strString) > 10
        strNewString = Mid(strString, InStr(strString, ":") + 1)
        If Left(strNewString, 1) = " " Then
            MsgBox Mid(strNewString, 2, 16)
        End If
        strString = Mid(strNewString, 17)
    Wend

okay now you've lost me completely :p

Quote:

---

I have several lines that are like this:

5:16pm up 9 min(s), 1 user, load average: 0.03, 0.06, 0.04

I just want this part of the line(0.03, 0.06, 0.04)

---

Sounds like he wants everything past the last ":" character, no? :confused:

Maybe we will have to see what the original poster says....

I was also taking the subject of the post: "Take part of all lines in a text box" ....
meaning that the text box had multiple lines in it.


If we take it that the text box only has one line in it, then a simple InStrRev looking for the ":" is all that is needed.

I still can't get the last part of each line to the text box, i have tried this to take the part that i don't want, but the result is nothing, i don't know what i am doing wrong:

/
XP = FrmPrincipal.Text1

Do While Len(XP) > 10
XPP = Left(XP, 60)
If Left(XPP, 1) = " " Then
MsgBox Mid(XPP, 1, 60)
XP = Replace(XP, XPP, "")
End If
XP = Mid(XPP, 17)
Loop

/

someone has any idea about this?
thank's in advance:confused:

Do While Len(XP) > 10
XPP = Left(XP, 60)

At this point you only have 60 characters in XPP. You have thrown away the rest of the text box. Is this what you wanted to do??

If Left(XPP, 1) = " " Then
MsgBox Mid(XPP, 1, 60)
XP = Replace(XP, XPP, "")
End If

You show the MsgBox ONLY if the first character is a space.
What did you intend the "Replace" statement to do?

How about replacing that bit of code with this and see if its what you wanted:

VB Code:

Do While Len(XP) > 10
        ' find where the colon is in the string
        x = InStr(1, XP, ": ")
        ' grab the rest of the string, after the colon
        XPP = Mid(XP, x + 2)
        ' display the first 17 characters
        MsgBox Left(XPP, 17)
        ' Loop around, with the rest of the string
        XP = Mid(XPP, 17)
    Loop