Solve for x.http://vbforums.com/attachment.php?s=&postid=1168554
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I'm sorry but that answer is wrong. At least I think. Havent done it in some time. Let me check!
im sticking by my answer ;) http://www.vbforums.com/
the suspense is killing me :eek:
Log4 (8*cubert(32)) - Log4 (2)
=Log4 (8*cubert(32)) - 1/2
=Log4 (8) + Log4 (cubert(32)) - 1/2
=Log2 (8)/Log2 (4) +Log4 (cubert(32)) -1/2
=3/2 - 1/2 + Log4 (cubert(32))
=2/2 + Log4 2(cubert(4))
=1 + Log4 (2) + Log4 (4)/3
=1 + 1/2 + 1/3
=6/6 + 3/6 + 2/6
=11/6
Oh nice good job steve!
*bows* :p
Lol guess my memory fails me! Again, it wouldnt be the first time. Try the other ones i have up! http://vbforums.com/showthread.php?s=&threadid=198278
I figured multiplication, I thought that was part of the radical bar, thats how I write mine..
it was multiplication
4^x=4*(32)^(1/3)
4^x=2*4*4^(1/3)
I think you missed a 4.
Wouldnt it be:
4^x=4*(32)^(1/3)
4^x=4*(2*4*4)^(1/3)?
Tell me if i'm wrong?
sure ur right but so am i
?
you are correct but so am i
4^x=4*(2*4*4)^(1/3)
is correct
Guess what bugz! Your confusing me again!
4^x=4*(32)^(1/3)
4^x=4*(23*4)^(1/3)
4^x=2*4*(4)^(1/3)
I still dont see where the 4 went?
what 4?
actually nm your right bugz