percent riddle.

Igor,Stanislav, and Vladimir are walking down the street. They each have a certain whole number of rubles with them(currency). It is known that Igor has 240% of what Vladimir has, and that Igor has 25% of the difference of what Vladimir and Stanislav have. It is known that Igor's money squared is less than 20% of Stanislav's money squared, and that Stanislav has more money than Vladimir's money squared * 2. At least how much does each one have? Can this be solved? First one with an answer+explanation wins.

looks like its just a system of equations and inequalities. i'll use the first letter in their name to represent each individual's cash, so we have:


i=2.4v :1
i=(v+s)/4 :2
i^2<(s^2)/5 :3
s>v^2 :4

1 & 2: 2.4v=(v+s)/4

2.15v=s/4
8.6v=s :5

4 & 5: v<8.6 :6
5 & 1: i=12s/43

SBS

i^2=(12/43)^2*s^2 :7

3&7: (12/43)^2*s^2<(s^2)/5

12/43<1/5

but the inequality is false. so it can't happen.

Let Igor have i rubles, let Stanislav have s rubles, and let Vladmir have v rubles. (i,s,v) are positive integers.

i=(240%)*v
i=(12/5)*v (1)
i=(25%)*(s-v)
i=(1/4)*(s-v) (2)
i^2 < (20%)*(s^2)
i^2 < (1/5)*(s^2) (3)
s > 2*(v^2) (4)
Equate (1) and (2):
(12/5)*v=(1/4)*s-(1/4)*v
s=(53/5)*v (5)
Subst (5) into (4):
(53/5)*v > 2*(v^2)
2*(v^2)-(53/5)*v < 0
10*(v^2)-53*v < 0
v*(10*v-53) < 0
Since v > 0, 10*v-53 < 0
10*v<53
v<53/10
Since v is an integer, v</=5
From (5): s=(53/5)*v,
Thus, v=5, s=53
Subst v into (1):
i=12

Thus, Igor has 12 rubles, Stanislov has 53 rubles, and Vladmir has 5 rubles.

Bugz:

Quote:

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i=(v+s)/4 :2

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It is actually i=(s-v)/4, as stated in the problem:

Quote:

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Igor has 25% of the difference of what Vladimir and Stanislav have

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excellent kalkewl8ter. I am very impressed.;) Bugz, don't worry about it. You show me up in here most of the time anyway.:p

oops:D thats what i get for posting when i usually sleep:p;)