removing last 5 or 6 chars

ive got a ip like: <ip>:<port>

i wanna strip teh :<port>

there what i came up with

Code:

---

        bool passed=false;
        for(int i=0;i<=strlen(server_name);i++){
                if(passed){
                        *server_name=' ';
                } else{
                        if(*server_name==':'){
                                *server_name=' ';
                                passed=true;
                        }
                }
                *server_name++;
        }

---

it returns the lst 8 with the port, and i cant figure out why :confused:

Code:

---

char *buf;
buf = server_name;
buf+=strlen(server_name) -1;
while(*buf!=':'){
      *buf-- = 0x00;
}
*buf = 0x00;
}

---

voila...

what is 0x00?

null character

cool!! where do you see all these weird characters?

Quote:

---

Originally posted by prog_tom
cool!! where do you see all these weird characters?

---

They are at the end of every string.

how come I never seen any of them, previously?:mad:

0x00 = 0

it's hexadecimal....

and what you call weird character is ASCII caracter.

in all C++ book it have an introduction about that.

Quote:

---

Originally posted by jim mcnamara

Code:

---

char *buf;
buf = server_name;
buf+=strlen(server_name) -1;
while(*buf!=':'){
      *buf-- = 0x00;
}
*buf = 0x00;
}

---

voila...

---

it returns a blank :confused:

huh? this code prints everything up to but not inclusing the ':'

Code:

---

#include <stdio.h>
int main(){
 char server_name[100];

 char *buf;
 memset(&server_name,0x00,sizeof(server_name));
 strcpy(server_name,"101.101.0:asb");
 buf = server_name;
 buf+=strlen(server_name) -1;
 while(*buf!=':'){
      *buf-- = 0x00;
  }
 *buf = 0x00;
  printf("%s\n",server_name);
}

---

The only possible difference is that server_name here is an sz string.