Well it seems most people describing their problems on here could do with this to check their algebra (me included sometimes):
try QuickMath.com
Oh and u don't need to reply to this...
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Well it seems most people describing their problems on here could do with this to check their algebra (me included sometimes):
try QuickMath.com
Oh and u don't need to reply to this...
if u plot y=x^(0.5) you'll see points above the x axis, meaning that you only get one y value for each x value. so when x=4, you won't see (4,2) and (4,-2) but just (4,2). that justifies my point on our arguement.
I just tried that and you are right. I thinkg those values you can set in advanced mode must do something towards revealing the negative side of the graph, as I doubt a seemingly big online utility such as that would have made sucha a foolish mistake as to leave it out...
sorry to tag on to your every post, Masterbandit.
I attempted to plot y=x^(1/2). since y=x^(1/2) is just another way of writing f(x)=x^(1/2), it is also suppose to give one value. also if you want to display the lower half of the graph, simply set the boundaries of y from -4 to 4 before you graph it. btw my graphing calculator does the same thing the website did. also if you try to solve x=4^(1/2), it will give you x=2. it attempts to graph the equation. since simiplifying LHS just takes the principal square root of 4, it attempts to graph x=2, which cross the y axis at (2,0), but not (-2,0) so only solution showed up is x=2, not x=-2. and I myself, is still convinced that the solution to that is simply x=2, and x=-2 is not a solution (unless i have mistakened your original meaning in the other post)