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I have a long that is under 255 and I want to convert it to a char.
I'm loading into into an array of char's but only want this first number to go into the first element of the array.
When I use ltoa I end up with
array[0] = 2
array[1] = 5
array[2] = 5
I'd like
array[0] = 255
THanks
is your question how to asign a char to a long(ex. 'a'=97) then
long lNumber=255;
char szArray[10];
szArray[0]=(char)lNumber;
I think you can do this way:
Not sure if it's "itoa" or "atoi".PHP Code:long lNumber = 255;
char szArray[20];
itoa((int)lNumber, szArray,10);
long int num;
char ch[10];
ch[0]=(char)num;
if you need a fast way to split the number between the array's chars you can use:
ch[0]=(char)(num&0x000000ff); \\save the first byte
ch[1]=(char)(num&0x0000ff00); \\save the second byte
ch[2]=(char)(num&0x00ff0000); \\save the third byte
ch[3]=(char)(num&0xff000000); \\save the fourth byte
that way you'll be able to save more then one char on a long number.
to save the chars to it use:
num=char; //where char is the first number you want to save
num+=char<<8; //that'l save the first char and add another one
num+=char<<16; //adds the third one
num+=char<<24; //adds the forth one
[QUOTE]Originally posted by Mr.Fixit
[B]long int num;
char ch[10];
ch[0]=(char)num;
if you need a fast way to split the number between the array's chars you can use:
ch[1] to ch[3] would be 0 since the chars would only concern the low byte.Quote:
ch[0]=(char)(num&0x000000ff); \\save the first byte
ch[1]=(char)(num&0x0000ff00); \\save the second byte
ch[2]=(char)(num&0x00ff0000); \\save the third byte
ch[3]=(char)(num&0xff000000); \\save the fourth byte
*(long*)ch=num;
would do (and be a lot faster), the reverse process would be
num=*(long*)ch;
my mistake there:
needed to SHR after the masking...
(>>8 for the second byte >>16 for the third and so on)
but your way seem to do the job with greater clearity and ease ;-)
yeah :) but if you want them in reverse order then your way would be best ;)