Is there a difference?

Is there a difference for division when you use "/" or "\"?

The \ returns an Integer, whereas the / returns a floating-point.

yes there is, but what exactly do you mean? those 2 chars use to show up here and there in the IT world.

Yes Matthew, there is a difference.
The backslash must return an integer and it rounds numbers.

e.g 2.5 \ 1.5 rounds to 3\2 or 1.5 which is then rounded to 1. In other words it returns how many 1.5's are in 2.5 in whole numbers, answer - only 1.

I hope I explained that right, but that's basically how it works

GRAHAM :)

Quote:

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Originally posted by Megatron / floating-point

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What do you mean when you say that?

It means that there will be decimals at the end.

Code:

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45 \ 6 = 7
45 / 6 = 7.5

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Get what I mean?

Yup, I understand. It's like this:

Code:

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45 \ 6 = 7 = (rounded)
45 / 6 = 7.5 = (exact)

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but the \ operator is HEAPS quicker.

if you have a loop with intensive math, you're better off multiplying your 3 dec vars by 1000, holding them in Long's and using the \ type. the overhead to calculate floating points, singles and doubles is very high.


and it's not rounded!

100 goes into 99 zero times, it never rounds up.

99 / 100 = 0.99
99 \ 100 = 0

which is why it's faster, it doesn't calculate the modulus

[Edited by Paul282 on 05-31-2000 at 08:53 PM]

There's a subtle point to what the good people here say relative to the / and \ operators. It's very easy to unwittingly declare an integer, long or byte datatype and then via VB's weak type-casting, waste a huge amount of CPU cycles doing floating-point arithmetic.

For example:

Code:

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Dim X AS Integer
  X = 7/3    ' bad kitty method
            '  processor does backflips to return 2.33333
            '  which is then type-cast to a result of 2

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