Filling an array with a string

How would one go about putting the characters of a sting into the index of an array?
eg.
For i = 1 To 8
array(i) = "abcdefgh"
Next
I want array(1) to be a , array(2) to be b and so on.
Thanks

Code:

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memset(arr,'\0',sizeof(arr));  // zero out the array
for (i=1;i<9;i++){
    arr[i-1] = i; 
}

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The problem is: arrays start counting with zero, and zero is used by C to mark the end of a string so:

Code:

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arr[0]=0;

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will create an array with no length - like a null string in VB.
So,

Code:

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arr[0]=' ';

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or something like that for the first element

or this

Code:

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char c;
int i=0;
for (c='a';c<='h';c++){
    arr[i++]=c;
}

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my problem is I have no idea what you want.... :D