Easy date question

hehe you can't do it that way.

$query = "INSERT INTO Guests (UserName, Email, Comments, date("Ymd")) Values('$UserName', '$Email', '$Comments', '$Date')";


date("Y-m-d") is a value not the name of the field. so do it like this


$query = "INSERT INTO Guests (UserName, Email, Comments, date)) Values('$UserName', '$Email', '$Comments', 'date("Y-m-d") ')";

Shouldn't it be:

PHP Code:

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$query = "INSERT INTO Guests (UserName, Email, Comments, date)) Values('$UserName', '$Email', '$Comments', 'date(\"Y-m-d\")')"; 


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very possible. if it doesn't work the way I have it you can try hobos way. or you can try this


$query = "INSERT INTO Guests (UserName, Email, Comments, date)) Values('$UserName', '$Email', '$Comments', '".date("Y-m-d")."')";

OK, some of them worked kind of and some didn't work at all. The ones that worked kind of would add the record, but the date would be 0000-00-00.

This is the one that worked from sscout sans a stray parenthesis.

$query = "INSERT INTO Guests(UserName, Email, Comments, Date) Values('$UserName', '$Email', '$Comments', '".date("Y-m-d")."')";

What are the "dots" doing? Why does this work?

well it is hard to say. but the . makes it so it leaves the anotation of the select statement and lets you use " in the code. kind of like adding it to itself.


echo "todayts date = ". date("y-m-d") ;

does pretty much the samething. does tha tmake sense?

Not to me :(

Thanks for trying and at least it works. I'll figure it out eventually.