simple Math prob. how to colculate?

Sups,
I'm sorry, but i dont know the english word for it, but i'm tryin to write a lil app which will colculate 'functions' like 2x*x + 5x + 3.
which goes like this:
x1,2 = (b*b something (-4)*a*c) /2
I hope u guys knows what i'm talkin about :D:D
well, my question is how can i colcuate the 'other' action of b*b?
sorry, bad english. PLZ CHECK attachment for a picture.
tnx!

x1=(b*b +sqr( (-4)*a*c)) /2
x2=(b*b -sqr( (-4)*a*c)) /2

Hope this helps,

that finds the roots of a parabola. :)

Rofl, parabola yea...
If you will the graph it will be a parabola but how can i write the marked part in the pic ive attached in VB?

VB Code:

'I want this
Sqr(9) = 3

You sure i can do it with 'sqr'?

that makes my nose bleed

Oooo...Quadratic equations...That takes me back to GCSE maths :D
Glad you weren't asking to solve a 3D Intergration formula...*shudder*