convert binary to Hex

How to do this without getting overflow errors?

I need to convert 111111111111111111111111111

to hex

That is all

Seahag

VB Code:

Public Function BinaryToDecimal(BinaryString As String) As Long
    If (Not Len(BinaryString) > 1023) Then
        Dim retVal As Double
        If (BinaryString <> "") And (Replace(Replace(BinaryString, "1", ""), "0", "") = "") Then
            Dim i As Long
            BinaryString = StrReverse(BinaryString)
            For i = 0 To Len(BinaryString)
                If (Mid(BinaryString, i + 1, 1) = 1) Then
                    retVal = retVal + (2 ^ (i))
                End If
            Next i
        End If
        BinaryToDecimal = retVal
    Else
        MsgBox "Overflow would occur"
        Exit Function
    End If
End Function
 
Private Sub Form_Load()
    Dim strHex As String
    
    strHex = Hex(BinaryToDecimal("10000"))
End Sub

NOTE: the binaryTodecimal function is courtesy of plenderj :)

That is gold..
Thanks for clearing that up :)

The above code will convert a limited size Binary number (31 bits) to a Hex Number.

If you want any size Binary Number to a Hex number, then try this...

Code:

---


Private Sub Form_Load()
  Debug.Print BinToHex("1100101100101100010101011010010101111010100101011010010100101100110101110111101010100101100101101001010")
End Sub


Private Function BinToHex(ByVal BinVal As String) As String
  Dim FourBits As String
  Dim BinValPosition As Integer
  Dim BitPosition As Integer
  Dim DigitValue As Integer
 
  BinVal = StrReverse(BinVal)
 
  For BinValPosition = 1 To Len(BinVal) Step 4
    FourBits = Mid(BinVal, BinValPosition, 4)
    DigitValue = 0
    For BitPosition = 1 To Len(FourBits)
      If Mid(FourBits, BitPosition, 1) = "1" Then
        DigitValue = DigitValue + 2 ^ (BitPosition - 1)
      End If
    Next BitPosition
    BinToHex = Mid("0123456789ABCDEF", DigitValue + 1, 1) & BinToHex
  Next BinValPosition
 
End Function

---

Cool thanks all
:)