How to find VBCRLF ( char 13 ) in a String

Here is what I have but it does not work !

Code:

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public static String Daok(String varStr)
  {
  int i=0;
  for (i=0; i < varStr.length ();i++)
  {
    if (varStr.charAt (i) == 13)
      System.out.println ("One Enter Found");
  }
  return "-----> " + varStr + " <-----";
  }
}

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Never ever use ASCII in a Java program. Everything's Unicode.

Code:

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System.out.println(someString.indexOf('\n'));

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Code:

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    if (varStr.charAt (i) == varStr.indexOf ('\n'))
      //ACTION HERE

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That does not work

Do not loop through the string, my code returns the first index of a newline.

ok but I want to know each place of each VbCrLf and it return only the number 27 ?

Read these: http://java.sun.com/j2se/1.3/docs/api/index.html ; specifically the one for the String class

Also, just a theory:

Code:

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for (int i = 0; i < s.length(); i++)
{
    if (s.charAt(i) == '\n')
    {
        System.out.println("Found newline at " + i);
    }
}

---

Thx for the code!

Thx for the link ! I searched in java.sun.org something like that but I did not achieve to any good result! :)

Thx you

Ive been looking at a lot of networking code lately and i know that Unix usually termanates a line with a linefeed (\n) Mac a carriage return (\r) and Windows a carriage return linefeed pair
(\r\n).

So Daok you should be able to test for bolth. :p