Arithmetic Sequence

Please find the formula for the sequence whose common difference is 201 and the 2nd term is 5.5

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Originally posted by prog_tom
Please find the formula for the sequence whose common difference is 201 and the 2nd term is 5.5

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Sorta Simple, I think.

My guess is You are trying to find a Linear Equation of the Format:

Y = mX + b.

I would think m = 201.

Now, all you need to do is find b when Y = 5.5, and X = ?.

Now, by the second term, you mean X = 2?
Or, as some sequences go, the first term could mean X = 0, thus making the Second X = 1.

So, If you know if X is = 2, or X = 1, then you can finish solving for b.

-Lou

oh dear...

you want the nth term right ???

The nth term of a series in A.P

T_n = a + (n-1)*d

a = First Term
d = Common Difference

Now T₂ = 5.5 , d = 201

There fore a = 5.5-201 = -195.5

So .. T_n = -195.5 + (n-1)*201

T_n = -195.5 + 201n - 201

T_n = (201*n)-396.5

The winner is:
thinktank2@

Are you really at Arctic? Isn't it freezing out there? You have INet access???

Yeah...Next door to Saint Nicholas :p

Quote:

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Originally posted by prog_tom
The winner is:
thinktank2@

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Congrats!!!
:D

*goes down on one knee*

i didn't understand the question myself :(