Quick question about arc cotangent

ok, i know that cotangent (cot) = (1/tan(theta))

but, does the arc cotangent (cot^-1(theta)) = (1/tan^-1(theta))?

thanks a lot

i should say, if not, what does it equal, or how do you calculate it.

Cotangent(Angle) = 1 / Tangent(Angle)

Arc-cotangent( X ) = Arctangent( 1 / X )

If Arc-cotangent( X ) = Angle, then Cotangent( Angle ) = X and Tangent( Angle ) = 1 / X

In VB Land, if you want Arc-Cotangent( X ), use Atn( 1 / X )

For degrees, Tangent( Angle ) = Cotangent( 90 - Angle )
For radians, Tangent( Angle ) = Cotangent( Pi / 2 - Angle )

So Cotangent( X ) = Pi / 2 - Atn( X )

I think I have the above correct. I hardly ever use cotangent. In school, they bother you with cotangents. In real life, you can almost always work with the tangent. In real life, you almost always are working with a right triangle or (x, y) coordinates. You can use the ratios that are tangents instead of the ratios that are cotangents.

thanks guv :)