PHP Dir list

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Nov 1st, 2001, 08:40 PM
Wynd

PHP Dir list

PHP Code:

<? $dir_name = "C:\site"; $dir = opendir($dir_name); $file_list = "<ul>"; while ($file_name = readdir($dir)) { if (($file_name != ".") && ($file_name != "..")) { $file_list .= "<li>$file_name</li>"; } } $file_list .= "</ul>"; closedir($dir); ?> <html> <head> <title>Files in <? echo "$dir_name"; ?></title> Files in: <? echo "$dir_name"; ?> <? echo "$file_list"; ?> </body> </html>

Is there a way I can just put this in a directory and have it list the files for that dir, and not have to manually specify the dir to list the files of?
Nov 1st, 2001, 09:59 PM

try this:

$dir_name="./";
Nov 2nd, 2001, 02:03 AM
da_silvy

I don't think you would get the wanted effect for the $dir_name printout then....

But other than that, it works ;)
Nov 2nd, 2001, 09:03 PM
Wynd

Yeah, well, the bad comes with the good but oh well. Thanks :)
Nov 2nd, 2001, 09:48 PM
da_silvy

What about having good with good:

This should be what you are looking for:

Did you want the absolute path or just directory name?

Absolute Path:

PHP Code:

<? $dir_name = "./"; $dir = opendir($dir_name); $file_list = "<ul>"; while ($file_name = readdir($dir)) { if (($file_name != ".") && ($file_name != "..")) { $file_list .= "<li>$file_name</li>"; } } $file_list .= "</ul>"; closedir($dir); ?> <html> <head> <title>Files in <? echo getcwd(); ?></title> Files in: <? echo getcwd(); ?> <? echo "$file_list"; ?> </body> </html>
Nov 2nd, 2001, 09:53 PM
da_silvy

Just the directory's name:

PHP Code:

<? $dir_name = "./"; $dir = opendir($dir_name); $file_list = "<ul>"; while ($file_name = readdir($dir)) { if (($file_name != ".") && ($file_name != "..")) { $file_list .= "<li>$file_name</li>"; } } $file_list .= "</ul>"; closedir($dir); $dir = substr(strrchr(getcwd(), "\\"), 1); ?> <html> <head> <title>Files in <? echo $dir; ?></title> Files in: <? echo $dir; ?> <? echo "$file_list";?> </body> </html>
Nov 4th, 2001, 10:28 AM
sail3005

how would you get the full path of the files?
Nov 4th, 2001, 06:43 PM
da_silvy

I think you mean showing

Bullet: c:\apache\htdocs\index.php?

Here you go:

PHP Code:

<? $dir_name = "./"; $dir = opendir($dir_name); $file_list = "<ul>"; while ($file_name = readdir($dir)) { if (($file_name != ".") && ($file_name != "..")) { $filename = getcwd()."\". $file_name; $file_list .= "<li>getcwd()\$file_name</li>"; } } $file_list .= "</ul>"; closedir($dir); ?> <html> <head> <title>Files in <? echo getcwd(); ?></title> Files in: <? echo getcwd(); ?> <? echo "$file_list"; ?> </body> </html>
Nov 4th, 2001, 07:08 PM
sail3005

thanks, but, i get an error with it. :confused:
Nov 4th, 2001, 08:16 PM
Wynd

No, what I meant was the relative path i guess. Like if I put the file in C:\site\folder\dir\images\ it should say "Files in images/", if I put it in C:\site\db\ it should say "Files in db/", etc.
Nov 4th, 2001, 08:26 PM
da_silvy

Quote:

Originally posted by Wynd
No, what I meant was the relative path i guess. Like if I put the file in C:\site\folder\dir\images\ it should say "Files in images/", if I put it in C:\site\db\ it should say "Files in db/", etc.

Have a look at my second post with code in it.

That does what you want ^^^^ here. ;)

Sail, what does the error say?
Nov 4th, 2001, 08:31 PM
da_silvy

Yeah, sorry sail, I didn't test the code that i posted before, try this:

PHP Code:

<? $dir_name = "./"; $dir = opendir($dir_name); $file_list = "<ul>"; while ($file_name = readdir($dir)) { if (($file_name != ".") && ($file_name != "..")) { $cwd = getcwd(); $file_list .= "<li>$cwd\\$file_name</li>"; } } $file_list .= "</ul>"; closedir($dir); ?> <html> <head> <title>Files in <? echo getcwd(); ?></title> Files in: <? echo getcwd(); ?> <? echo "$file_list"; ?> </body> </html>
Nov 5th, 2001, 04:38 PM
sail3005

cool, works now, thanks. :D
Nov 5th, 2001, 07:27 PM
Wynd

Well that's partly what I want. I just want the script to output the directory name, not the whole path. (C:\path\dir\images produces "Files in images", C:\otherpath\scripts produces "Files in scripts", etc)
Nov 6th, 2001, 12:04 AM
da_silvy

Have you tried this code yet:

I posted it before. :rolleyes:

PHP Code:

<? $dir_name = "./"; $dir = opendir($dir_name); $file_list = "<ul>"; while ($file_name = readdir($dir)) { if (($file_name != ".") && ($file_name != "..")) { $file_list .= "<li>$file_name</li>"; } } $file_list .= "</ul>"; closedir($dir); $dir = substr(strrchr(getcwd(), "\"), 1); ?> <html> <head> <title>Files in <? echo $dir; ?></title> Files in: <? echo $dir; ?> <? echo "$file_list";?> </body> </html>

It does what you want...
Nov 6th, 2001, 06:59 PM
Wynd

Thanks, it works. One thing though, you forgot to escape the backslash, that threw me for a loop till i figured it out :o
Nov 7th, 2001, 02:30 AM
da_silvy

Woops, I didn't actually, but the php tags did that.

If you quote my message, you will see that i didn't forget to escape it ;)
Nov 22nd, 2001, 01:28 AM
sail3005

is there anyway to tell it how to sort the files?

Like by, date modified, size, name, etc?
Nov 22nd, 2001, 01:53 AM
da_silvy

can't test it, but you should be able to load it into an array then sort the array...
Nov 22nd, 2001, 09:29 AM
sail3005

how would i load it into an array?
Nov 23rd, 2001, 02:40 PM
sail3005

any ideas please?
Nov 23rd, 2001, 07:16 PM
da_silvy

I think it's pretty difficult

I will have heaps of free time in a week, i'll figure something out, so just PM me. ;) after thursday - (no more exams ;))
Nov 23rd, 2001, 09:36 PM
sail3005

Alright, i'll remember. ;)
Nov 23rd, 2001, 10:09 PM
da_silvy

good for you

i think it would be quite difficult

can't remember if php can handle multiple dimension arrays :eek:
Nov 23rd, 2001, 11:37 PM
sail3005

that would be bad if it didn't. it would certainly make things difficult
Nov 24th, 2001, 01:25 AM
da_silvy

i was thinking though

It could be put into a normal array, depending on what order they want

i.e.

By FIlename

then the string =

"filename, size, " etc

By size

then the string =

"size, filename, " etc

then you sort the array
and split it
Nov 24th, 2001, 11:49 AM
sail3005

sounds good. i still have no idea how to do it though. :(
Nov 27th, 2001, 04:27 AM
da_silvy

here you go.

hope that works.

PHP Code:

<? $dir_name = "./"; $dir = opendir($dir_name); $myint = -1; while ($file_name = readdir($dir)) { if (($file_name != ".") && ($file_name != "..") && !is_dir($file_name)) { $myint++; $file_list[0][$myint] = "$file_name"; $file_list[1][$myint] = filesize($file_name); $file_list[2][$myint] = filemtime($file_name); } } //asort($file_list[0]); Sort by filename //asort($file_list[1]); Sort by filesize //asort($file_list[2]); Sort by modified time asort($file_list[1]); while (list($key) = each($file_list[1])) { print $file_list[0][$key].",".$file_list[1][$key].",".$file_list[2][$key]."<br>"; } ?>
Nov 27th, 2001, 06:38 PM
Wynd

The only part that works is the file size part. And, the filename and date parts print in the same order.
Nov 27th, 2001, 06:47 PM
Wynd

Nm, got it to work. I have been looking for this for a long time. Thanks for the help!
Nov 28th, 2001, 01:53 AM
da_silvy

No probs, what was the problem?

Did you quote the message and then copy that source or what?
Nov 28th, 2001, 06:23 PM
Wynd

I just c&p'ed ity from the web page. In this part:

PHP Code:

each($file_list[1])

you need to change "1" to 0, 1, or 2 depending on what you want.
Nov 29th, 2001, 03:01 AM
da_silvy

oh yeah, woops i should've mentioned that in my other post :|

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