char to int

Code:

---

int convert()
{
        char str[10];
        int len;
        int ret,i;

cout<<"Enter a binary value";
cin>> str;

len = strlen(str);

int val;

for(i=len;i>=0;i--){
        val = atoi(str[i]);//error here
        //ret = pow(val, i);
        cout << val<<endl;
        return 0;
}
}

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i get the error : cannot convert parameter 1 from 'char' to 'const char *'

what do i have to do to correct it? thanks

How about just atoi('x')? :p

Quote:

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Originally posted by MPrestonf12

Code:

---

int convert()
{
        char str[10];
        int len;
        int ret,i;

cout<<"Enter a binary value";
cin>> str;

len = strlen(str);

int val;
char str2[2];

for(i=len;i>=0;i--){
              str2[0]=str[i];
              str2[1]='\0';       
              val = atoi(str2);//error here
        //ret = pow(val, i);
        cout << val<<endl;
        return 0;
}
}

---

---

How about that? the parameter to atoi must be a string which end with null('\0'). cannot be a single char by itself.

Better to use kedaman's method here.converting char type to int

Quote:

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Originally posted by CornedBee
Also, I recommend replacing isbin by a macro in C and an inline function in C++.

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Why?

Wouldnt a macro be more efficient? Less overhead? inline functions still have to get processed....

No. if you optimize for speed (not code size), inlines will behave just like macros.

CB is right. Think about what a macro does. The compiler expands the macro and puts the code in the position where the macro was already.

When you inline f() it takes the f() code and moves it to the position where the function is called. Expands all the code onto the line - just like a macro.