Unary &~

How do I find the address-of the one's complement of 15 (&~15 (C++ code)) in VB? At least I think that's how it is said. :eek: :)

Thanks

I know C, but I'm finding that people asking for C stuff out of context means that I usually give a bad answer.

Post the code you got this from.

To answer your question -

Code:

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Dim a as long
a = 15
z = varptr(a)

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z is now a pointer to a
If this is for a function call, pass z ByVal.

I'm not sure how to do a one's complement with VB.

Here is the code:

Code:

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bmp.bmWidthBytes = ((bmp.bmWidth + 15) &~15)/8;

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And I saw somewhere were perhaps a one's complement can be acheived some how with Not?

Thanks

Oh. That's what I thought.

Code:

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((bmp.bmWidth + 15) &~15)/8;

should be:
((bmp.bmWidth + 15) &  ~15)/8;
which is
( bmp.bmwidth + 15)  and  one's complement of 15
not the address of.

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You are right, not does give one's complement, except in VB I"ve gotten wierd results. If you want to assume not will work-- this is your code:

Code:

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dim i as long
 i=  (bmp.bmwidth + 15)  and ( not 15)
 i = i/8
 bmp.bmWidthBytes = i

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