Round Up Floating Point

ok I understand.

If you want an inline approach, this is the way:

double y=(int)(x*100.0)/100.0;

you power the radix by -decimal (a negative decimal gives precision lower than 1. Note the floating point division.

for variable radix or amount of decimals you can use this generic expression:

double z;
int r=10,d=2;
double y=(int)(x*(z=pow(r,d)))/z;

Here is another way, Kedaman's is more succinct

Code:

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double roundup2(double f){
        double tmp;
        char t[20];
        char *stopstr;       
        tmp= 5 * pow(10,-3. );
        tmp += f;
        memset(t,'\0',sizeof(t) );
        sprintf(t,"%10.2f",tmp);  // << truncate the value and put in string
        return strtod(t,&stopstr);      //  << return a float from the string
}

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