Logfont

how come when i do this:

Code:

---

char *facename = "Arial";

      LOGFONT lf;
      lf.FaceName = facename;

---

it gives me an error..
thanks

What error are you getting?

stuff similar to this

cannot convert from 'char [6]' to 'char [32]'

does it give you that error when you declare the char or when you try to set the FaceName to "facename"(Arial)?

use strcpy